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ValentinkaMS [17]
3 years ago
13

Solve and describe the steps used to find x for the equation 2(x + 4) – 10 = 12

Mathematics
1 answer:
Lorico [155]3 years ago
3 0
Well,  you want to find the value of x.  
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Write equivalent fractions for 3^3 bottom 4 and 1^2 bottom 3
Rufina [12.5K]

\tt \dfrac{3^3}{4}=\dfrac{27}{4}\\\\\dfrac{1^2}{3}=\dfrac{1}{3}

5 0
2 years ago
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Factor the polynomials comletely, then solve 9x^2 +66x+21 = 0​
son4ous [18]

Answer:

x= -1/3

x = -7

Step-by-step explanation:

9x^2 +66x+21 = 0​

a=9 b=66 c=21

quadratic formula

x=(-b +/- square root of (b^2 – 4ac))/(2a)

x = (-66 +/- square root of (66^2 -4*9*21))/(2*9)

x = (-66 +/- square root of (4356 -756))/(18)

x = (-66 +/- square root of (3600))/(18)

x = (-66 +/- 60)/18

split the fraction

(-66 +/- 60)/18 = -6/18 and -126/18 because of the +/-

x = -6/18  x = -126/18

x = -1/3   x = -7

7 0
2 years ago
Read 2 more answers
Jameson Middle School gives bottles of water to teachers and students who are going on a field trip. The school orders 500 bottl
qaws [65]

Answer:

up to 232

Step-by-step explanation:

Let x = number of students

The number of bottles for the students is 2x since they give 2 bottles per student.

2x + 35 = 500

2x = 465

x = 232.5

Answer: 232

8 0
2 years ago
A dust particle weighs 7.42 x10
kogti [31]

Answer:

how to answer this actually

Step-by-step explanation:

btw my answer is 704.2

4 0
3 years ago
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a rectangular garden is 3ft longer than it is wide. its area is 460 ft squared. what are its dimensions​
LUCKY_DIMON [66]

Answer:

$\large \boxed{\text{23 ft by 20 ft}}

Step-by-step explanation:

        Let x = the width of the garden

Then x + 3 = the length of the garden

Area of garden = length × width

                      A = lw = x(x+ 3)

\begin{array}{rcl}x( x+ 3)& = & 460\\x^{2} + 3x& = &460\\x^{2} + 3x - 460& = &0\\x + 23 = 0 & \text{or} & x - 20 = 0\\x = -23 & \text{or} & \mathbf{x = 20}\\\end{array}

 width = x                    = 20 ft

length = x + 3 = 20 +3 = 23 ft

\text{The dimensions of the garden are $\large \boxed{\textbf{23 ft by 20 ft}}$}

Check:

\begin{array}{rcl}20(20 + 3) & = &460\\20(23) & = & 460\\460 & = & 460\\\end{array}

OK.

5 0
3 years ago
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