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timama [110]
3 years ago
11

Dr. Jon planned to reward his class with candy because everyone got a A on the test. He surveyed every 4th student that entered

his class to find out which candy he should buy . Which type of sample did he use?
Mathematics
1 answer:
USPshnik [31]3 years ago
8 0
This is an example of a systematic sample.

Dr. Jon developed a system in order to get a random sample. His plan was to survey the 4th student that entered his classroom.
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Find the Factors of 18 and 30
Artyom0805 [142]

Answer:

A

Step-by-step explanation:

18=1×18=18

2×9=18

. 3×6=18

6×3=18

9×2=18

18×1=18

30=1×30=30

2×15=30

3×10=30

5×6=30

6×5=30

10×3=30

15×2=30

30×1=30

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What is the domain of {(1, 3) (4, 3) (6, 2)}?
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Domain means the set of x values. So the domain would be 1,4,6
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Answer:

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Step-by-step explanation:

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3 years ago
Which expressions are completely factored? Select each correct answer. 18y^3−6y=3y(6y^2−2) 32y^10−24=8(4y^10−3) 20y^7+10y^2=5y(4
Vladimir79 [104]

Answer:

The expressions that completely factored are:

32y^{10}-24 = 8(y^{10}-3) ⇒ 2nd

16y^{5}+12y^{3}=4y^{3}(4y^{2}+3) ⇒ 4th

Step-by-step explanation:

Complete factorization means the terms in the bracket has no common factor

∵ The expression is 18y³ - 6y

- Find the greatest common factor of the numbers and the variable

∵ The greatest common factor of 18 and 6 is 6

∵ The greatest common factor of y³ and y is y

∴ The greatest common factor is 6y

- Divide each term by 6y to find the terms in the bracket

∴ 18y³ - 6y = 6y(3y² - 1) ⇒ not the same with the answer

∵ The expression is 32y^{10}-24

∵ The greatest common factor of 32 and 24 is 8

∴ The greatest common factor is 8

- Divide each term by 8 to find the terms in the bracket

∴ 32y^{10}-24 = 8(  y^{10}-3)  ⇒ the same with the answer

∴ The expression 32y^{10}-24 = 8(y^{10}-3) is completely factored

∵ The expression is 20y^{7}+10y^{2}

∵ The greatest common factor of 20 and 10 is 10

∵ The greatest common factor of y^{7} and y² is y²

∴ The greatest common factor is 10y²

- Divide each term by 10y² to find the terms in the bracket

∴ 20y^{7}+10y^{2}=10y^{2}(2y^{5}+1) ⇒ not the same with the answer

∵ The expression is 16y^{5}+12y^{3}

∵ The greatest common factor of 16 and 12 is 4

∵ The greatest common factor of y^{5} and y³ is y³

∴ The greatest common factor is 4y³

- Divide each term by 4y³ to find the terms in the bracket

∴ 16y^{5}+12y^{3}=4y^{3}(4y^{2}+3) ⇒ the same with the answer

∴ The expression 16y^{5}+12y^{3}=4y^{3}(4y^{2}+3) is completely factored

The expressions that completely factored are:

32y^{10}-24 = 8(y^{10}-3)

16y^{5}+12y^{3}=4y^{3}(4y^{2}+3)

3 0
3 years ago
The quotient of 19,008/16
oksano4ka [1.4K]
I don’t know if you’ve ever heard of the amazing device known as a calculator but the answer is 1,188
7 0
4 years ago
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