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Olin [163]
3 years ago
12

2x2-x-6 = 0 What is one solution to the equation?

Mathematics
2 answers:
barxatty [35]3 years ago
8 0

Answer:

x1=2 and x2 =-3/2

Step-by-step explanation:

2x^2-x-6=0 (quvadratic equation)

a=2, b=-1, c=-6

x1=(-b+sqrt(b^2-4ac))/2a

x1=(-(-1)+sqrt((-1)^2 - 4*2*(-6)))/2*2

x1 =(1+sqrt (1+48))/4

x1= (1+sqrt(49))/4

x1 =(1+7)/4

x1=8/4

x1=2

x2=(-b-sqrt(b^2-4ac))/2a

x2=(1-7)/4

x2=-6/4

x2=-3/2

NeTakaya3 years ago
6 0

Answer:

X=2

Step-by-step explanation:

<em><u>Easy, easy!</u></em>

<em><u /></em>

<u><em>Let's use trial and error!</em></u>

Since we can factor this equation, let's do it!

2x^{2} -x-6=0\\2x^{2} -x=6\\x(2x-1)=6\\\\

So this means that we have 2 factors: x and (2x-1)

Those 2 factors multiplied by each must other equal 6.

So at the top of my head two numbers that multiplied by each other equal 6 are 3 and 2.

Let's try x=3 and (2x-1)=2

Since x=3,

(2x-1)=2\\(2(3)-1)=2\\(6-1)=2\\(5)\neq 2

It means that we should keep trying!!!

Let's try x=2 and (2x-1)=3

Since x=2,

(2x-1)=3\\(2(2)-1)=3\\(4-1)=3\\3=3

So we have our answer!!!

x=2

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Step-by-step explanation:

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2 years ago
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mash [69]

Answer: OPTION B.

Step-by-step explanation:

Given the following System of equations:

\left \{ {{3x-5y=19} \atop {x+y=1}} \right.

You can use the Elimination Method to solve it. The steps are:

1. You can mutliply the second equation by -3.

2. Then you must add the equations.

3. Solve for the variable "y".

Then:

\left \{ {{3x-5y=19} \atop {-3x-3y=-3}} \right.\\.....................\\-8y=16\\\\y=\frac{16}{-8}\\\\y=-2

4. Now that you know the value of the variable "y", you must substitute it into any original equation.

5. The final step is to solve for "x" in order to find its value.

Then:

x+(-2)=1\\\\x=1+2\\\\x=3

Therefore, the solution is:

(3,-2)

8 0
4 years ago
What is (x2 + 9x+ 18) / (x+6)
ohaa [14]

Answer:

x+3

Step-by-step explanation:

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lubasha [3.4K]
If you paid attention in math, you would know this lol jk.
But you would rewrite it as 5+4
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