All categories

3 years ago

Someone help me please !!!

Mathematics

1 answer:

son4ous [18]3 years ago

7 0

I believe the correct answer here would be C. x=10/3 because it is the only proportional answer.

You might be interested in

Chris

Rainbow [258]

Answer:

meat = $2.40

vegetables = $ 2.40

fruit = $2.40 + X

= 2.40 ÷ 2

= 1.2

therefore 2.40 + 1.2

=$3.6 (For fruits )

= $3.6 + $2.40 + $2.40

= $ 8.4

Hope this helps .Plzz mark me brainliest

7 0

3 years ago

There’s a picture attached xox

NARA [144]

1) 6 positive
2) - $25 negative
3) -8 negative
4) 82 positive

5 0

3 years ago

What is infinity / infinity?

bixtya [17]

Answer:

undefined

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

The estimated daily living costs for an executive traveling to various major cities follow. The estimates include a single room

Alexandra [31]

Answer:

$\bar x = 260.1615$

$\sigma = 70.69$

The confidence interval of standard deviation is: $53.76$ to $103.25$

Step-by-step explanation:

Given

$n =20$

See attachment for the formatted data

Solving (a): The mean

This is calculated as:

$\bar x = \frac{\sum x}{n}$

So, we have:

$\bar x = \frac{242.87 +212.00 +260.93 +284.08 +194.19 +139.16 +260.76 +436.72 +355.36 +.....+250.61}{20}$

$\bar x = \frac{5203.23}{20}$

$\bar x = 260.1615$

$\bar x = 260.16$

Solving (b): The standard deviation

This is calculated as:

$\sigma = \sqrt{\frac{\sum(x - \bar x)^2}{n-1}}$

$\sigma = \sqrt{\frac{(242.87 - 260.1615)^2 +(212.00- 260.1615)^2+(260.93- 260.1615)^2+(284.08- 260.1615)^2+.....+(250.61- 260.1615)^2}{20 - 1}}$ $\sigma = \sqrt{\frac{94938.80}{19}}$

$\sigma = \sqrt{4996.78}$

$\sigma = 70.69$ --- approximated

Solving (c): 95% confidence interval of standard deviation

We have:

$c =0.95$

So:

$\alpha = 1 -c$

$\alpha = 1 -0.95$

$\alpha = 0.05$

Calculate the degree of freedom (df)

$df = n -1$

$df = 20 -1$

$df = 19$

Determine the critical value at row $df = 19$ and columns $\frac{\alpha}{2}$ and $1 -\frac{\alpha}{2}$

So, we have:

$X^2_{0.025} = 32.852$ ---- at $\frac{\alpha}{2}$

$X^2_{0.975} = 8.907$ --- at $1 -\frac{\alpha}{2}$

So, the confidence interval of the standard deviation is:

$\sigma * \sqrt{\frac{n - 1}{X^2_{\alpha/2} }$ to $\sigma * \sqrt{\frac{n - 1}{X^2_{1 -\alpha/2} }$

$70.69 * \sqrt{\frac{20 - 1}{32.852}$ to $70.69 * \sqrt{\frac{20 - 1}{8.907}$

$70.69 * \sqrt{\frac{19}{32.852}$ to $70.69 * \sqrt{\frac{19}{8.907}$

$53.76$ to $103.25$

8 0

2 years ago

Evaluate the function found in the previous step at X =-3

babunello [35]

$x-5y=-4x-2y$

In order to evaluate the given function at x = -3, simply replace "x" in the function with -3 and solve.

$-3-5y=-4(-3)-2y$

Multiply -4 and -3 in the function above.

$-3-5y=12-2y$

Add 3 on both sides of the equation.

$-3-5y+3=12-2y+3$ $-5y=15-2y$

Add 2y on both sides of the equation.

$-5y+2y=15-2y+2y$ $-3y=15$

Divide both sides of the equation by -3.

$\frac{-3y}{-3}=\frac{15}{-3}$ $y=-5$

Therefore, at x = -3, the value of y = -5. Hence, f(-3) = -5.

Answer:

f(-3) = -5

7 0

1 year ago