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3 years ago

Nicole reads 24 pages during a 30 minute independent reading period.At this rate how many pages would she read in 45 minutes

Mathematics

1 answer:

hjlf3 years ago

5 0

Answer:

36 pages

Step-by-step explanation:

divide 24 by 30=0.8 and multiply 0.8x45.

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What is the mode for the set of data? 6,7,10,12,12,13 10 12 13 11

KonstantinChe [14]

12
because it is the only number that appears more than once which is basically the definition of mode.

4 0

3 years ago

Consider the transformation T: x = \frac{56}{65}u - \frac{33}{65}v, \ \ y = \frac{33}{65}u + \frac{56}{65}v

irina1246 [14]

Answer:

Step-by-step explanation:

$T: x = \frac{56}{65}u - \frac{33}{65}v, \ \ y = \frac{33}{65}u + \frac{56}{65}v$

$\frac{d(x,y)}{d(u,v)} =\left|\begin{array}{ccc}x_u&x_v\\y_u&y_v\end{array}\right|$

$=(\frac{56}{65} )^2+(\frac{33}{65} )^2\\\\=\frac{(56)^2+(33)^2}{(65)^2} \\\\=\frac{4225}{4225} \\\\=1$

B )

$S:-65 \leq u \leq 65, -65 \leq v \leq 65$

$T(65,65)=(x=\frac{56}{65} (65)-\frac{33}{65} (65),\ \ y =\frac{33}{65} (65)+\frac{56}{65} (65)\\\\=(23,89)$

$T(-65,65)=(-56-33,\ \ -33+56)\\\\=(-89,23)$

$T(-65,-65) = (-56+33,-33-56)\\\\=(-23,-89)$

$T(65,-65)=(56+33, 33-56)\\\\=(89,-23)$

$\int \!\! \int_{T(S)} \ x^2 + y^2 \ {dA}$

$=\int\limits^{65}_{v=-65} \int\limits^{65}_{u=-65}(x^2+y^2)(\frac{d(x,y)}{d(u,v)} du\ \ dv$

Now

$x^2+y^2=(\frac{56}{65} u-\frac{33}{65} v)^2+(\frac{33}{65} u+\frac{56}{65} v)^2$

$[(\frac{56}{65} )^2+(\frac{33}{65}) ^2]u^2+[(\frac{33}{65} )^2+(\frac{56}{65}) ^2]v^2$

$=\frac{(65)^2}{(65)^2} u^2+\frac{(65)^2}{(65)^2} v^2=u^2+v^2$

$\int \!\! \int_{T(S)} \ x^2 + y^2 \ {dA}$

$=\int\limits^{65}_{v=-65} \int\limits^{65}_{u=-65}(u^2+v^2) du\ \ dv$

$=\int\limits^{65}_{-65}\int\limits^{65}_{-65}u^2du \ \ dv+\int\limits^{65}_{-65}\int\limits^{65}_{-65}v^2du \ \ dv$

By symmetry of the region

$=4\int\limits^{65}_0 \int\limits^{65}_0u^2 du \ \ dv + u\int\limits^{65}_0 \int\limits^{65}_0v^2 du \ \ dv$

$= 4(\frac{u^3}{3} )^{65}_{0}(v)_0^{65}+(\frac{v^3}{3} )^{65}_{0}(u)_0^{65}\\\\=4[\frac{(65)^4}{3} +\frac{(65)^4}{3} ]$

$=\frac{8}{3} (65)^4$

8 0

3 years ago

Help me please! I can't figure this out

Alina [70]

First we need to look at the greatest and least points on each axis.

For x - the greatest is 2 and the least is -2 (that is the value of x for the points marked in the top left and right quadrants of the xy axis.

(Note that the points on the number line have a value for x of 1 & -1, but you need to look at highest value of points in all quadrants.)

For y - the greatest would be 3 and the least 0. Looking up and down the Y axis, you can see these intersections for the points given.

Now you need to find the D & R that is suitable for these values. We can only consider the first and last option because it correctly shows that the values for x & 7 must be between 2 & -2 and 0 and 3, The first one is incorrect because they have the D & R reversed. It is x that must be between 2 & -2 and y that must be between 0 & 3.

I hope you found this helpful.

7 0

4 years ago

I need help asap please please

Dvinal [7]

I believe the one you have selected is correct.

4 0

3 years ago

Read 2 more answers

How many millions are in a trillion?

vlada-n [284]

10000 millions or 999 billion is 1 trillion

4 0

3 years ago