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kap26 [50]
3 years ago
15

Which is the best strategy to use to solve this problem? Sophie wants to make a large rectangular sign that has an area of 60 sq

uare feet. She wants to put a border around the sign, but she wants to use as little border material as possible. What are the dimensions Sophie should use for this sign?
A. Write a number sentence. Use a number sentence to calculate the area of a rectangle. Use guess and check to find two numbers that when multiplied will give a product of 60.

B. Make a list. Create a list of all possible whole-number combinations of length and width that would equal an area of 60 square feet. Then start calculating the perimeter of each rectangle. Look for a pattern to decrease the number of calculations you have to make.

C. Use objects to model the problem. Arrange 60 square tiles in different patterns that create a rectangular shape. Count the number of tiles on the perimeter of each of the shapes.
Mathematics
1 answer:
OverLord2011 [107]3 years ago
8 0
Answer: All of the plans could get you to the correct answer. However, being able to write and solve an equation would generally be the fastest. Therefore, I would chose choice A.

In this problem, you are dealing with 2 separate equations. First, you need to find the volume, so A = LW. And you are also dealing with the perimeter formula, P = 2L + 2W.

All you need to do is find option for the area that gives the smallest perimeter.
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I need help with these 2 questions!! please 20 points!!!
bezimeni [28]

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Answer:

  1. 45 cm²
  2. 38 cm²

Step-by-step explanation:

The conventional way to work these problems is to make use of the formulas for areas of a triangle, rectangle, and semicircle. If you've used these formulas for a while, you recognize that they give you certain relationships that may make these problems easy to do mentally.

__

1. The area of a triangle is half the product of height and width, so is equivalent to the area of a rectangle either half as high, or half as wide. We note that the width of the sail is 5 cm, so half that is 2.5 cm--exactly the same as the height of the boat's hull. That means we can add the height of the sail to the length of the boat, and the total area can be considered to be the same as that of a rectangle that is

  2.5 cm high × (12 cm + 6 cm) long = (2.5)(18) cm² = 45 cm²

__

2. The usual formula for the area of a circle is ...

  A = πr²

When expressed in terms of diameter, this becomes ...

  A = π(d/2)² = (π/4)d²

Then the area of a semicircle is half that, or (π/8)d². This is equivalent to the area of a rectangle that is "d" wide and "π/8·d" high. That is, the approximate area of the semicircle is that of a rectangle 4 cm high by (π/8·4 cm) = π/2 cm wide. In other words, the semicircle effectively adds π/2 cm to the left end of the 6 cm central rectangle of the figure.

As discussed above, the area of a triangle is equivalent to the area of a rectangle half as high. In this figure, the triangle is 10-6 = 4 cm wide, so can be considered to contribute 4/2 = 2 cm to the right end of the 6 cm central rectangle.

If we consider π ≈ 3, then the approximate area of the figure is ...

  (4 cm)(3/2 cm + 6 cm + 2 cm) = (4)(9.5) cm² = 38 cm²

__

The exact value is 4(8+π/2) = 32+2π ≈ 38.283 cm².

7 0
3 years ago
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