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ElenaW [278]
3 years ago
5

A rectangular sticker is 9 centimeters tall and 5 centimeters wide. What is its area?

Mathematics
1 answer:
shutvik [7]3 years ago
6 0

The correct answer should be : 45.

Since to find the area of the rectangle we have to use the formula :

Area = width x length

9 x 5 = 45.

Hope this helps,

Davinia.

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3 .912+s=5.313 evaluate
taurus [48]

Answer:

s= 1.401

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3 0
2 years ago
If f(x) = 3x2 – 4 and g(x) = 2x - 6, what is g(f(2))?
saveliy_v [14]

Answer:

10

Step-by-step explanation:

find out f(2)

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then g(8) = 16 - 6= 10

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3 years ago
__,__, 8.16,32,64 what is the arithmetic sequence?
seraphim [82]

Answer:

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Step-by-step explanation:

There are a couple of ways one could approach this. The goal is to find out the factor by which the numbers are increasing. Looking at going from 8 -> 16, we have either added 8, or doubled 8. So the factor is either +8 or x2. Going from 16 -> 32, adding 8 no longer holds true, while multiplying by 2 (doubling 16) does. To confirm what we have found, we can further check our math by using the final two numbers, 32 -> 64, to confirm that the sequence pattern is to double the current number to achieve the next number.

Working backwards, we can half each number to find out the first two numbers in the sequence. 64/2 = 32, 32/2 = 16, 16/2 = 8, 8/2 = 4, 4/2 = 2

8 0
3 years ago
(Write the fraction as a mixed number) Anyone able to help out with my 4 questions?
s344n2d4d5 [400]
Yes !  I can help you.

-- Take each fraction.

-- Do the division . . . (top number) divided by (bottom number) .

-- Write the whole number from the quotient.
    Save the remainder.

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   Copy the original bottom number to the bottom of the fraction.

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Bada-bing !  There's your mixed number.
7 0
3 years ago
Read 2 more answers
Hi guys i need help solving −2.4n−3 and −7.8n+2.
Airida [17]

Answer:

-5 = -5.4n

Step-by-step explanation:

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add 2.4 to both sides

which would give you

-3 = -5.4n + 2

then you would subtract -2 from both sides

and -5 = -5.4n  and this is one solution

5 0
3 years ago
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