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2 years ago

8

If A=60 and B=60, then find the value of tanA(A+B) = tanA + tanA/1- tanA .tanB

1 answer:

mihalych1998 [28]2 years ago

6 0

Answer:

your answer is 160

Step-by-step explanation:

just add 60+60_160 u might have to add because its tanned

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Find the angle between vector u=i+sqrt 7 j and vector v=-i-4j to the nearest degree.

kenny6666 [7]

Answer:4

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

When 60% of a number is added to the number, the result is 208<br>

NNADVOKAT [17]

Answer:

x=120

CK

0.60*120=72

120+72=192

192=192

Hope this helps

Step-by-step explanation:

THE ANSWER IS 192

6 0

2 years ago

1. What is the solution of the system?

andreyandreev [35.5K]

Answer:

The given system of equations has solutions below:

1) The solution is (2,3)

2) The solution is ( $\frac{-8}{7}, \frac{5}{7}$ )

3) The solution is infinitely many solutions

4) No solution

Step-by-step explanation:

Given system of equation are

$-x+2y=4\hfill (1)$

$-4x+y=-5\hfill (2)$

To solve equation by using elimination method

Multiply eqn (2) into 2

$-8x+2y=-10\hfill (3)$

Now subtracting (1) and (3)

$-x+2y=4$

$-8x+2y=-10$

_________________

7x=14

x= $\frac{14}{7}$

$x=2$

Substitute x=2 in equation (1)

-2+2y=4

2y=4+2

$y=\frac{6}{2}$

y=3

Therefore the solution is (2,3)

2) Given equation is

$-2x+y=3\hfill (1)$

4y-4=x

Rewritting as below

$x-4y=-4\hfill (2)$

To solve equation by using elimination method

multiply (2) into 2

$2x-8y=-8\hfill (3)$

Adding (1) and (3)

-2x+y=3

2x-8y=-8

________

-7y=-5

$y=\frac{5}{7}$

substitute $y=\frac{5}{7}$ in (1)

$-2x+\frac{5}{7}=3$

$-2x=3-\frac{5}{7}$

$-2x=\frac{21-5}{7}$

$x=-\frac{8}{7}$

Therefore the solution is ( $\frac{-8}{7},\frac{5}{7}$ )

3) Given equation is $6x+2y=10\hfill (1)$

$3x+y=5\hfill (2)$

equation (1) can be written as

2(3x+y)=10

$3x+y=\frac{10}{2}$

3x+y=5

Therefore equations (1) and (2) are same therefore it has infinitely many solutions

4) Given equation is $-x-2y=14\hfill (1)$

$-2x-4y=12\hfill (2)$

multiply equation (1) into 2

$-2x-4y=28\hfill (3)$

To solve equation by using elimination method

subtracting (2) and (3)

-2x-4y=28

-2x-4y=12

_______

$28\neq -12$

therefore it has no solution

4 0

2 years ago

Solve the expressions on the left when x=5<br>3x-10<br>x^2-15<br>5x-21<br>x+10-8

Nitella [24]

Answer:

5

10

4

7

Step-by-step explanation:

Apply the value of x into the expressions:

3(5) - 10 = 15 - 10

= 5

5² - 15 = 25 - 15

= 10

5(5) - 21 = 25 - 21

= 4

5 + 10 - 8 = 15 - 8

= 7

5 0

2 years ago

Read 2 more answers

Need help with a simple problem 2^x=3^x+1

KiRa [710]

For $x\ \textgreater \ 0$ , $2^x\ \textless \ 3^x$ , all the more $2^x\ \textless \ 3^x+1$ , therefore no solution.

For $x=0$ , we have $2^0=3^0+1 \Rightarrow 1=1+1 \Rightarrow 1=2$ . Obviously that' false.

For $x\ \textless \ 0$ both $2^x$ and $3^x$ , where $2^x\ \textgreater \ 3^x$ , belong to the range $(0,1)$ , then $3^x+1$ belong to the range $(1,2)$ .
Those ranges don't have a common part, therefore, again, no solution.

So, the equation $2^x=3^x+1$ doesn't have a solution.

4 0

2 years ago