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Inessa [10]
3 years ago
5

F(x) = x5 – 8x4 + 16x3?

Mathematics
2 answers:
rodikova [14]3 years ago
6 0

Answer:

Step-by-step explanation:

The first guy got it backwards

Thre first solution is 4

The second solution is 0

Julli [10]3 years ago
5 0

Answer:

The graph touches, but does not cross, the x–axis at x = 4

The graph of the function crosses the x–axis at x = 0

Step-by-step explanation:

just took the test

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Calculate x Give your answer correct to 1 d.p. Х 35° 15 cm<br> it is a trigonometry question.​
OlgaM077 [116]

Here we are finding x, given the angle and adjacent side. To find x we will use the function cos as cos = a/h.

So let's do cos(35°) = 15cm / x

cos(35°) = 0.8 (1 dp)

x = 15 cm / cos(35°)

x = 18.3 cm (1 dp)

6 0
2 years ago
A jeweler is dividing 3/8 of a pound of rubies amount 4 lots. What part of a pound will each lot weight?
ch4aika [34]
They will each equal 1.5 pounds also known as 1 1/2 or 3/2.
5 0
3 years ago
2) Ivan is making meatloaf. He used the amount of catsup shown in the measuring cup. Are the units Ivan used to measure the cats
DedPeter [7]
Iván used to measure the catsup the same as those given
7 0
3 years ago
B) Find g (-3) for g(x) = 3x + 5
fredd [130]

Step-by-step explanation:

g(x)=3x+5

g(-3)=3(-3)+5

=-9+5

=-4

3 0
3 years ago
The price of a certain computer stock t days after it is issued for sale is p(t)=100+20t−6t^2 dollars. The price of the stock in
Elanso [62]

Answer:

0 < t < \frac{5}{3}

After 1.67 days the stocks would be sold out.

Step-by-step explanation:

The price of a certain computer stock after t days is modeled by

p(t) = 100 + 20t - 6t²

Now we will take the derivative of the given function and equate it to zero to find the critical points,

p'(t) = 20 - 12t = 0

t = \frac{20}{12}

t = \frac{5}{3} days

Therefore, there are two intervals in which the given function is defined

(0, \frac{5}{3}) and (\frac{5}{3}, ∞)

For the interval (0, \frac{5}{3}),

p'(1) = 20 - 12(1) = 20

For the interval (\frac{5}{3}, ∞),

p'(2) = 20 - 12(2) = -4

Positive value of p'(t) in the interval (0, \frac{5}{3}) indicates that the function is increasing.

0 < t < \frac{5}{3}

Since at the point t = 1.67 days curve is showing the maximum, so the stocks should be sold after 1.67 days.

7 0
3 years ago
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