Answer:
The answer is 2427.5
Step-by-step explanation:
The fraction consists of two numbers and a fraction bar: 4,855/200
The number above the bar is called numerator: 4,855
The number below the bar is called denominator: 200
The fraction bar means that the two numbers are dividing themselves.
To get fraction's value divide the numerator by the denominator:
Value = 4,855 ÷ 200
To calculate the greatest common factor, GCF:
1. Build the prime factorizations of the numerator and denominator.
2. Multiply all the common prime factors, by the lowest exponents.
Factor both the numerator and denominator, break them down to prime factors:
Prime Factorization of a number: finding the prime numbers that multiply together to make that number.
4,855 = 5 × 971;
4,855 is a composite number;
In exponential notation:
200 = 2 × 2 × 2 × 5 × 5 = 23 × 52;
200 is a composite number;
Okay so 11/4 needs to be multiplied by 2 so that the D match up.
so 11/4 x 2 = 22/8
22/8 - 3/8 = 19/8
The difference is 19/8
Answer:
6
Step-by-step explanation:
You have a total area of 2,200 sq units to cover... and each can of paint covers 400 sq units. So, you'll need:
2200 sq units / 400 sq units/can = 5.5 cans
In such problems, we always round up, since you will need 5 full cans of paint, and half of a 6th can.
So, in total you will need 6 cans of paint to cover all 2,200 sq units.
Answer:
The net forces exerted on the horse and cart are not the same, so they are not balanced forces.
Step-by-step explanation:
Please see the Newton's 2nd Law which states that an object accelerates if there is a net or unbalanced force on it. In this scenario there is just one force exerted on the wagon i.e: the force that the horse exerts on it. The wagon accelerates because the horse pulls on it. And the amount of acceleration equals the net force on the wagon divided by its mass.
As there are two forces the push and pull the horse; the wagon pulls the horse backwards, and the ground pushes the horse forward. The net force is determined by the relative sizes of these two forces.
If the ground pushes harder on the horse than the wagon pulls, there is a net force in the forward direction, and the horse accelerates forward, and if the wagon pulls harder on the horse than the ground pushes, there is a net force in the backward direction, and the horse accelerates backward.
If the force that the wagon exerts on the horse is the same size as the force that the ground exerts, the net force on the horse is zero, and the horse does not accelerate.
