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3 years ago

Factor the given expression. 64^3-343

Mathematics

2 answers:

Mashcka [7]3 years ago

5 0

63³-343 = 261801

Factor the following integer:

261'801

The sum of the digits of 261801 is 2 + 6 + 1 + 8 + 0 + 1 = 18, which is divisible by 9. This means 261801 is too.

261801 = 9×29089:

261801 = 9×29089

9 = 3^2:

261801 = 3^2×29089

Because 29089 is odd, only test odd numbers for divisibility.

29089 is not divisible by 3, 5, 7, 9, 11, 13, 15 or 17.

29089 = 19×1531 which means 29089 is divisible by 19:

261801 = 3^2×19×1531

3 is prime:

261801 = 3^2×19×1531

Because 19 is odd, only test odd numbers for divisibility.

19 is not divisible by 3.

Since 19 is not divisible by any integer up to 4, it is prime:

261801 = 3^2×19×1531

Because 1531 is odd, only test odd numbers for divisibility.

1531 is not divisible by 3, 5, 7, 9, 11, 13, 15, 17, 19, 21, 23, 25, 27, 29, 31, 33, 35, 37 or 39.

Since 1531 is not divisible by any integer up to 39, it is prime:

261801 = 3^2×19×1531

There are 2 copies of 3, 1 copy of 19 and 1 copy of 1531 in the product:

Answer: 261801 = 3^2×19×1531

balu736 [363]3 years ago

3 0

Your answer is 261201

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The cube less the square of a number is twice the number. If x is a positive integer, what is its value

olga55 [171]

Answer:

Step-by-step explanation:

let 'x' = number

x³ - x² = 2x

x³- x² - 2x = 0

x(x² - x - 2) = 0

x(x - 2)(x + 1) = 0

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2 years ago

The sum of two numbers is 25. Their difference is 9. What are the two numbers?

Lynna [10]

Using x and y as the numbers

x+y=25 -------#1
x-y=9 -------#2

Using addition of #1 and #2
x+y+x-y= 25+9
2x+0y=34
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x=17

Using the value of x and plugging said value into #1 or #2, we can find y
x=17

x+y=25
17+y=25
y=8

OR

x-y=9
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The numbers are 8 and 17

5 0

3 years ago

Read 2 more answers

A gas is said to be compressed adiabatically if there is no gain or loss of heat. When such a gas is diatomic (has two atoms per

Tems11 [23]

Answer:

The pressure is changing at $\frac{dP}{dt}=3.68$

Step-by-step explanation:

Suppose we have two quantities, which are connected to each other and both changing with time. A related rate problem is a problem in which we know the rate of change of one of the quantities and want to find the rate of change of the other quantity.

We know that the volume is decreasing at the rate of $\frac{dV}{dt}=-4 \:{\frac{cm^3}{min}}$ and we want to find at what rate is the pressure changing.

The equation that model this situation is

$PV^{1.4}=k$

Differentiate both sides with respect to time t.

$\frac{d}{dt}(PV^{1.4})= \frac{d}{dt}k\\$

The Product rule tells us how to differentiate expressions that are the product of two other, more basic, expressions:

$\frac{d}{{dx}}\left( {f\left( x \right)g\left( x \right)} \right) = f\left( x \right)\frac{d}{{dx}}g\left( x \right) + \frac{d}{{dx}}f\left( x \right)g\left( x \right)$

Apply this rule to our expression we get

$V^{1.4}\cdot \frac{dP}{dt}+1.4\cdot P \cdot V^{0.4} \cdot \frac{dV}{dt}=0$

Solve for $\frac{dP}{dt}$

$V^{1.4}\cdot \frac{dP}{dt}=-1.4\cdot P \cdot V^{0.4} \cdot \frac{dV}{dt}\\\\\frac{dP}{dt}=\frac{-1.4\cdot P \cdot V^{0.4} \cdot \frac{dV}{dt}}{V^{1.4}} \\\\\frac{dP}{dt}=\frac{-1.4\cdot P \cdot \frac{dV}{dt}}{V}}$

when P = 23 kg/cm2, V = 35 cm3, and $\frac{dV}{dt}=-4 \:{\frac{cm^3}{min}}$ this becomes

$\frac{dP}{dt}=\frac{-1.4\cdot P \cdot \frac{dV}{dt}}{V}}\\\\\frac{dP}{dt}=\frac{-1.4\cdot 23 \cdot -4}{35}}\\\\\frac{dP}{dt}=3.68$

The pressure is changing at $\frac{dP}{dt}=3.68$ .

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3 years ago

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Aleks04 [339]

Answer:

2x^3+10x^2+x+5

Step-by-step explanation

Answer to edge

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2 years ago

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What is the area of a section of pavement that is 10 ft wide and 70 yd long? Give your answer in square feet. I think I have th

Elenna [48]

Answer:

2100 ft²

Step-by-step explanation:

1 yard is 3 ft, so 70 yards is (70 yd)×(3 ft/yd) = 210 feet.

The area of the pavement is the product of its length and width:

area = (210 ft)(10 ft) = 2100 ft²

_____

If you keep the units with the numbers as I have done here, you find that the product of (10 ft) and (70 yd) does not have the units of ft². Rather, the units are ft·yd, which is <em>not what the problem is asking for</em>.

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3 years ago