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sweet-ann [11.9K]
3 years ago
13

What is the smallest part in your body

Biology
2 answers:
Aleks [24]3 years ago
4 0
What’s the smallest muscle in the human body? The stapedius, in your middle ear, measures about 1mm in size (or 1/26 of an inch). Connected to the stapes bone, it contracts to pull back the stapes and help protect your inner ear from loud noises. The stapedius also contracts to keep your own voice from sounding too loud in your head.
What’s the smallest bone in the human body?
Conveniently, that would be the stapes. It is one of three tiny bones in the middle ear that convey sound from the outer ear to the inner ear. Collectively called the ossicles, these bones are individually known as the malleus, incus, and stapes. Those are Latin words for the shapes the bones resemble: a hammer, anvil, and stirrup.
What’s the smallest organ in the human body?
You’ll find the pineal gland near the center of the brain, in a groove between the hemispheres. It’s not an organ like those in the abdominal cavity. It’s the human body’s smallest endocrine gland, and it produces melatonin, a hormone (derived from serotonin) that affects how we sleep, wake up, and react to seasonal changes. It’s called pineal because it’s shaped like a little pinecone.
What’s the smallest blood vessel in the human body? <span>Capillaries, the smallest, thinnest-walled blood vessels in the body, connect veins and arteries. They can be as small as 5-10 micrometers wide — or 50 times thinner than a baby’s hair. Each of us contains about 10 billion of them, with the average adult body containing about 25,000 miles of capillaries.</span>
pogonyaev3 years ago
4 0
It is a tiny bone called stapes located in the ear which transmit sound  from outer ear to the inner
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3 years ago
A performer, seated on a trapeze, is swinging back and forth with a period of 8.90 s. If she stands up, thus raising the center
iren2701 [21]

Answer:

8.800s

Explanation:

When the performer swings, she oscillates in SHM about Lo of the string with time period To = 8.90s.

First, determine the original length Lo, where for a SHM the time period is related to length and the gravitational acceleration by the equation

T = 2π×√(Lo/g)..... (1)

Let's make Lo the subject of the formulae

Lo = gTo^2/4π^2 ..... (2)

Let's put our values into equation (2) to get Lo

Lo = gTo^2/4π^2

= (9.8m/s^2)(8.90s)^2

------------------------------

4π^2

= 19.663m

Second instant, when she rise by 44.0cm, so the length Lo will be reduced by 44.0cm and the final length will be

L = Lo - (0.44m)

= 19.663m - 0.44m

= 19.223m

Now let use the value of L into equation (1) to get the period T after raising

T = 2π×√(L/g)

= 2π×√(19.223m/9.8m/s^2)

= 8.800s

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