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aivan3 [116]
3 years ago
9

Solve 3(w+2)=2w-1 what is w

Mathematics
1 answer:
sergejj [24]3 years ago
3 0
W = 12...............
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Determine the factors of x2 − 8x − 12.
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This polynomial cannot be factored because it is prime. Hope this helps. :)
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Sammy plans to build a kite He has two rods of lengths 4 feet and 3 feet Find the area of the material he will need to cover the
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6 0
2 years ago
If you assume that there are exactly 365 days in a year, how many seconds are there in one year? Give your answer to the nearest
Hunter-Best [27]
365*24*60*60=31536000s
So third option will be the answer
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4 years ago
A group of artists is selling small prints to raise money for charity. They sell p prints, and make a profit of f(p) on the sale
liraira [26]

The correct answer is is D) If the group sells 15 prints they will loose $85.

To figure out which statement is true, we have to evaluate the function ,

p(x)=17x-340 for all the values given in options (A)-(D).  A negative output represents a loss and  a positive output will represent a profit.

In A p=12 so f(12)=17\times 12-340=-136. In this case we gather that if they sell 12 prints, they will make a loss of $136. This tells us that option A is wrong.

In B, p=28 so f(28)=17\times 28-340=136. In this case we gather that if they sell 28 prints, they make a profit of $136. This tells us that option  B is wrong.

In C, p=35 so f(35)=17\times 35-340=225. In this case we gather that if they sell 35 prints, they make a profit of $225. This tells us that option  C is wrong.

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5 0
4 years ago
Multiply.
Nady [450]

\boxed{3\sqrt{22}\sqrt{58}\sqrt{18}=18\sqrt{638}}

<h2>Explanation:</h2>

Here we have the following expression:

3\sqrt{22}\sqrt{58}\sqrt{18}

So we need to simplify that radical expression. By property of radicals we know that:

\sqrt[n]{a}\sqrt[n]{b}=\sqrt[n]{ab}

So:

3\sqrt{22}\sqrt{58}\sqrt{18}=3\sqrt{22\times 58 \times 18}=3\sqrt{22968}

The prime factorization of 22968 is:

22968=2^3\cdot 3^2\cdot11\cdot 29

Hence:

3\sqrt{22968}=3\sqrt{2^3\cdot 3^2\cdot11\cdot 29}=3\sqrt{2^2\cdot 3^2\cdot 2\cdot 11\cdot 29}

By property:

\sqrt[n]{a^n}=a

So:

3\sqrt{2^2\cdot 3^2\cdot 2\cdot 11\cdot 29} \\ \\ 3(2)(3)\sqrt{2\cdot 11\cdot 29}=18\sqrt{638}

Finally:

\boxed{3\sqrt{22}\sqrt{58}\sqrt{18}=18\sqrt{638}}

<h2>Learn more:</h2>

Radical expressions: brainly.com/question/13452541

#LearnWithBrainly

3 0
3 years ago
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