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3 years ago

3 3/4 2 1/3 what is the area

Mathematics

1 answer:

wariber [46]3 years ago

8 0

Answer:

I'm guessing that those are the dimensions of a rectangle, so all you do is multiply them together, and you get (15/4)(7/3) = 35/4

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What is 30-60-90 when it comes to triangles

NeTakaya

It is a speacial right triangle. It always has 30,60, or 90 degrees.

4 0

3 years ago

The crime rate of a certain city is increasing by exactly

harina [27]

There will be about 450 crimes in the year 2015

6 0

4 years ago

Determine the quadratic function of 2,-3/5

Tanzania [10]

I guess you mean that the zeroes are 2 and -3/5.

In factor form the function could be

f(x) = (x - 2)(3x + 5)

expanding we get

f(x) = 3x^2 -x - 10

6 0

4 years ago

Which of the following represents the factorization of the binomial below?

Serggg [28]

Answer:

Step-by-step explanation:

x² - 81 ← is a difference of squares and factors in general as

a² - b² = (a + b)(a - b)

Here a = x and b = 9, thus

x² - 81 = (x + 9)(x - 9) → D

4 0

4 years ago

in a given year, the rate of flu infection for the general public was 8.3%. And sample of 200 people who receive the flu vaccine

makkiz [27]

Answer:

$\fbox{\begin{minipage}{10em}Option A is correct\end{minipage}}$

Step-by-step explanation:

Step 1: Define significance level

In this hypothesis testing problem, significance levels α is selected: $0.05$ , the associated z-value from Laplace table:

Φ( $z$ ) = α - $0.5 = 0.05 - 0.5 = -0.45$

=> $z$ = $-1.645$

Step 2: Define null hypothesis ( $H_{0}$ ) and alternative hypothesis ( $H_{1}$ )

$H_{0}$ : rate of flu infection $p$ = 8.3% or 8.3/100 = 0.083

$H_{1}$ : rate of flu infection $p$ < 8.3% or 8.3/100 = 0.083

Step 3: Apply the formula to check test statistic:

$K = \frac{f - p}{\sqrt{p(1 - p)} } * \sqrt{n}$

with $f$ is actual sampling percent, $p$ is rate of flu infection of $H_{0}$ , $n$ is number of samples.

The null hypothesis will be rejected if $K < z$

Step 4: Calculate the value of K and compare with $z$

$K = \frac{(\frac{3.5}{100}) - 0.083}{\sqrt{0.083(1 - 0.083)} } * \sqrt{200} = -2.46$

We have $-2.46 < -1.645$

=>This is good evidence to reject null hypothesis.

=> The actual rate is lower. (As $H_{1}$ states)

Hope this helps!

5 0

3 years ago