We have a line tangent to the circle with center B at point C. We know that the angle formed between the tangent line at the point of intersection to the line extended from that point to the center of the circle is equal to 90°. In the problem, the 90° is for ∠BCA. We also know that the summation of all angles in a triangle is 180°. We have the solution below for the ∠BAC
180°=∠BAC + ∠BCA + ∠ABC
180°=∠BAC + 90° + 40°
∠BAC =50°
The answer is 50°.
Answer:
See the attached image for solutions.
Step-by-step explanation:
X-ray vision to all students ratio:
<u>6:36</u>, which can be simplified to <u>1:6</u>.
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Flight to all students ratio:
<u>8:36</u>, which can be simplified to <u>2:9</u>.
Flight to inivisibility ratio:
<u>8:36</u>, which can be simplified to <u>2:3</u>.
Hope this helps! :)
Answer:
hi hope it helps
I=$336
Step-by-step explanation:
P=$3500, R=3.2%, T=3yrs and I=?
I=PRT/100
=3500x3.2x3/100
=33600/100
=$336
Answer:
8/3
Step-by-step explanation:
