Question

What is an expression equivalent to m^238/m^-79 in the form m^v, where v is an integer?

Answer 1

Answer:

$m^{317}$

Step-by-step explanation:

In indices, the division postulate is true:

$\frac{a^m}{a^n} = a^{m-n}$

Apply this to the question:

$\frac{m^{238}}{m^{-79}} \\= m^{238-(-79)}\\= m ^{238+79}\\= m^{317}$

Hence the expression expressed in the form $m^v \ is \ m^{317}$