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3 years ago

Use a special-product rule to factor the perfect-square trinomial. 81y^2+ 126y + 49

Mathematics

1 answer:

Ivahew [28]3 years ago

7 0

Answer:

The perfect -square trinomial

(9y+7)²

Step-by-step explanation:

Explanation:-

Given polynomial equation

81 y² + 126 y +49

⇒ 9² y² + 2(9)(7)y + 7²

⇒ (9y)² + 2(9)(7)y +7²

we will use formula

(a+b)² = a² + 2ab +b²

⇒ (9y+7)²

Final answer:-

The perfect -square trinomial

(9y+7)²

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4 years ago

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Answer:

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Step-by-step explanation:

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3 years ago

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lisov135 [29]

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4 years ago

Read 2 more answers

(1) [6pts] Let R be the relation {(0, 1), (1, 1), (1, 2), (2, 0), (2, 2), (3, 0)} defined on the set {0, 1, 2, 3}. Find the foll

goldenfox [79]

Answer:

Following are the solution to the given points:

Step-by-step explanation:

In point 1:

The Reflexive closure:

Relationship R reflexive closure becomes achieved with both the addition(a,a) to R Therefore, (a,a) is $(0,0),(1,1),(2,2) \ and \ (3,3)$

Thus, the reflexive closure: $R={(0,0),(0,1),(1,1),(1,2),(2,0),(2,2),(3,0), (3,3)}$

In point 2:

The Symmetric closure:

R relation symmetrically closes by adding(b,a) to R for each (a,b) of R Therefore, here (b,a) is: $(0,1),(0,2)\ and \ (0,3)$

Thus, the Symmetrical closure:

$R={(0,1),(0,2),(0,3)(1,0),(1,1)(1,2),(2,0),(2,2),(3,0), (3,3)}$

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3 years ago