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svp [43]
3 years ago
12

There are a total of 62 students in the robotics club and the science club. The science club has 8 fewer students than the robot

ics club. How many students are in the science club?
Mathematics
1 answer:
Lesechka [4]3 years ago
6 0
To find this answer you simply subtract eight from sixty-two, which gives you....
54! 
 
So there are 54 student in the science club!

Hope this helps! :)
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Los jornales de dos obreros suman S/.60. Si uno de ellos gana S/.12
8_murik_8 [283]

Answer:

Cada uno de ellos gana:

S/. 24

S/. 36

Step-by-step explanation:

Planteamiento:

a + b = 60

a = 12 + b

Desarrollo:

sustituyendo el valor de la segunda ecuación del planteamiento en la primer ecuación del planteamiento:

(12+b) + b = 60

2b + 12 = 60

2b = 60 - 12

2b = 48

b = 48/2

b = 24

de la segunda ecuación del planteamiento:

a = 12 + b

a = 12 + 24

a = 36

Check:

24 + 36 = 60

5 0
4 years ago
At a dog shelter, a 26-pound bag of dog food will feed 40 dogs. How many dogs would you expect to feed with a 13-pound bag of do
Inessa [10]
The 13 pound bag is 1/2 of the 26 pound bag so if 40 dogs eat that then 20 dogs will eat 13 pounds. 
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4 0
3 years ago
Simplify the following expression.
tankabanditka [31]
The answer is 2/3

or in decimal form: 0.6 repeated
7 0
3 years ago
What is 12 percent of 130?
maksim [4K]
12% of 130 is 15.6 hope it helps!

7 0
3 years ago
Read 2 more answers
Pumps A, B, and C operate at their respective constant rates. Pumps A and B, operating simultaneously, can fill a certain tank i
shepuryov [24]

Answer:D) 1 hr

Step-by-step explanation:

Given

Pump A and B can fill tank in \frac{6}{5} hr

Pump A and C can fill tank in \frac{3}{2} hr

Pump B and C can fill tank in 2 hr

Let A be the total hr taken A therefore rate of A=\frac{1}{A} /hr

Let B be the total hr taken B therefore rate of B=\frac{1}{B} /hr

Let C be the total hr taken C therefore rate of C=\frac{1}{C} /hr

\frac{1}{A}+\frac{1}{B}=\frac{5}{6}-----1

\frac{1}{B}+\frac{1}{C}=\frac{1}{2}-----2

\frac{1}{A}+\frac{1}{C}=\frac{2}{3}-----3

Adding 1,2 & 3

2(\frac{1}{A}+\frac{1}{B}+\frac{1}{C})=\frac{5}{6}+\frac{1}{2}+\frac{2}{3}

\frac{1}{A}+\frac{1}{B}+\frac{1}{C}=\frac{2}{2}

\frac{1}{A}+\frac{1}{B}+\frac{1}{C}=1

thus time taken by A,B and C combined is 1 hr

7 0
3 years ago
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