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ivann1987 [24]
3 years ago
10

What is theta in trigonometry?

Mathematics
2 answers:
Dennis_Churaev [7]3 years ago
7 0

Answer:

Theta is the acute angle which is used to find sin , cos , tan etc . for ex there are 2 acute angles in a right angle triangle . theta is one of them which we take to find other trigonometric values.

rewona [7]3 years ago
4 0
Theta is an acute angle in trigonometry!
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PLZ HELP! 20 POINTS!!
ivann1987 [24]
Given list of values
A = {23, 34, 19, 10, 9, 20, 40, 43, 28, 29, 36, 13, 27, 23, 36, 37, 7}

Sort list A to get list B
B = {7, 9, 10, 13, 19, 20, 23, 23, 27, 28, 29, 34, 36, 36, 37, 40, 43}

The smallest value is 7, so the min is 7
The largest value is 43, so the max is 43

Look through list B to find the middle-most value. What you can do is cross off each pair of outer values (see figure 1 in the attached images) until you are left with the middle value
Or you can note how there are 17 values so the median is at slot 9 (there are 8 values below the median; 8 values above the median; the 8 is from 17/2 = 8.5)

Once you know the median is 27, we split the list B into two parts
The first part, we'll call it L for lower half is
L = {7, 9, 10, 13, 19, 20, 23, 23}
which is the list of all values lower or smaller than the median.
The median of list L is 16 because its the midway point between 13 and 19. We can compute (13+19)/2 = 32/2 = 16. This is the value of Q1

The upper half U is
U = {28, 29, 34, 36, 36, 37, 40, 43}
this list shows all the values larger than the median.
The value of Q3 is 36. We find the midpoint of 36 and 36 which is just 36.
The value of Q3 is the same as the median of list U

------------------------------------------------

Five Number Summary:
Min = 7
Q1 = 16
Median = 27
Q3 = 36
Max = 43

This five number summary is then used to construct the box-and-whisker plot. See figure 2 in the attached images. The diagram shows how each piece of the boxplot is put together (eg: the left edge of the box is the value of Q1). 

5 0
3 years ago
The segment with endpoints (0,8) and (−6,0) is dilated to a segment with endpoints (0, 6) and (−4.5,0). What is the scale factor
sergiy2304 [10]
I think it would be 4/3 because when you multiply 8 by 4/3 you get 6 and when you multiply-6 by 4/3 you get -4.5 so

4/3
5 0
3 years ago
Solve: 28 − ≥ 7( − 4)<br> (show your work)<br> real answers only pls :(
ohaa [14]
You’ll distribute the 7 from (x-4) so your equation will be
28-x>_ 7x-28
then you’ll combine like terms (-x and 7x and 28 and -28
-56>_ -8x
divide by -8 on both sides and flip your sign
you’re answer is x<_7
x is less then or equal to 7
6 0
3 years ago
25.6% of what # is 21.12
laila [671]
To solve this problem, we are going to use the percent proportion, a/b = p/100, where a is the part of a number b, the whole, and p is the percentage out of 100.  
When we fill in our known integers into this equation, we get

21.12 / b = 25.6 / 100

Next, to simplify this equation, we should use cross products (means - extremes products theorem).  This means multiplying the numerator of one fraction and the denominator of the other fraction and setting them equal to one another.

21.12(100)=25.6(b)

When we multiply, you get

2112 = 25.6b

Finally, we divide both sides by 25.6, to get our variable b, alone, and without a coefficient.

82.5 = b

Therefore, 25.6% of the number 82.5 is 21.12.
7 0
3 years ago
Read 2 more answers
What is the volume of a hemisphere with a radius of 3 cm, rounded to the nearest tenth of a cubic centimeter?
Kaylis [27]

Formula: V = (2/3) π r 3.

Radius is 3cm.

So, now we can plug it in to solve for the volume.

V = (2/3) π 3^3

First, let's multiply 3^3.

3^3 = 27

Then, 27 x π = 84.82

After, multiply by 2/3.

84.82 x 2/3 = 56.55

Lastly, round 56.55 to the nearest tenth of a cubic centimeter.

56.55 = 56.6

Therefore the volume of a hemisphere with a radius of 3cm is 56.6cm^3.

8 0
3 years ago
Read 2 more answers
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