Hello!
To find the line perpendicular to the given line, y = 2x + 3, firstly, find the slope of the perpendicular line. To find it, use this format: -1/m, where m is the slope. It is also called the "negative reciprocal" of the slope of the given line.
Then, you substitute an ordered pair into a new slope-intercept equation (with the slope) and find the y-intercept.
-1/m when m = 2 → -1/2
y = -1/2x + b (substitute the given ordered pair)
-3 = -1/2(2) + b (simplify)
-3 = -1 + b (add 1 to both sides)
-2 = b | The y-intercept of the perpendicular equation is -2.
Therefore, the line perpendicular to the given equation, that also goes through the given ordered pair is y = -1/2x - 2.
The answer to the questions
Step-by-step explanation:
the answer is y=-6 when x=-3
Answer:
c = -5 and d = 1
Step-by-step explanation:
First, multiply out (cy^2)(4y^d). We get: 4cy^(2+d).
We equate this result to the right side of the equation: - 20y^3.
Then, equating the exponents and solving for d, we get: 2 + d = 3, or d = 1.
Equating the coefficients, we get 4c = -20, or c = -5.
1/8. Like 1/2 is half of 1, half of 1/2 is 1/4 and half of that is 1/8.
