Answer:
The answer has no solution because it is infinite and that's your vairiable
The answer would be 4X okay
35 Cars because, if you times 3 by 5 it equals 15 which means that 1 hour equals 5 cars. So you times 7 by 5 and that will give you the amount of cars that were washed.
9514 1404 393
Answer:
f(8) = -30 is the maximum
Step-by-step explanation:
The equation is that of a parabola in vertex form:
y = a(x -h)^2 +k . . . . . . . . (h, k) is the vertex; 'a' is the scale factor
Comparing this form to the given equation, we have ...
f(x) = -(x -8)^2 -30
That is, the scale factor is -1, and the vertex is (8, -30).
When the scale factor is negative, the graph opens downward and the vertex is a maximum. The maximum value is -30.
Answer:
Step-by-step explanation:
1.
cot x sec⁴ x = cot x+2 tan x +tan³x
L.H.S = cot x sec⁴x
=cot x (sec²x)²
=cot x (1+tan²x)² [ ∵ sec²x=1+tan²x]
= cot x(1+ 2 tan²x +tan⁴x)
=cot x+ 2 cot x tan²x+cot x tan⁴x
=cot x +2 tan x + tan³x [ ∵cot x tan x
=1]
=R.H.S
2.
(sin x)(tan x cos x - cot x cos x)=1-2 cos²x
L.H.S =(sin x)(tan x cos x - cot x cos x)
= sin x tan x cos x - sin x cot x cos x

= sin²x -cos²x
=1-cos²x-cos²x
=1-2 cos²x
=R.H.S
3.
1+ sec²x sin²x =sec²x
L.H.S =1+ sec²x sin²x
=
[
]
=1+tan²x ![[\frac{\textrm{sin x}}{\textrm{cos x}} = \textrm{tan x}]](https://tex.z-dn.net/?f=%5B%5Cfrac%7B%5Ctextrm%7Bsin%20x%7D%7D%7B%5Ctextrm%7Bcos%20x%7D%7D%20%3D%20%5Ctextrm%7Btan%20x%7D%5D)
=sec²x
=R.H.S
4.

L.H.S=



= 2 csc x
= R.H.S
5.
-tan²x + sec²x=1
L.H.S=-tan²x + sec²x
= sec²x-tan²x
=


=1