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Strike441 [17]
2 years ago
9

Help! QUICK! NO BOTS!

Mathematics
1 answer:
White raven [17]2 years ago
6 0

Answer:

number 2 or 4 but i think 2

Step-by-step explanation:

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Solve x42=37 x 42 = 3 7 using two different strategies. Explain each strategy.
Dafna11 [192]

Given equation : \frac{x}{42}=\frac{3}{7}.

Strategy 1: We can cross mutiply both sides remove fraction form.

On cross multiplication, we get

x * 7 = 3 * 42

7x = 126.

Dividing both sides by 7, we get

<h3>x = 18.</h3>

Strategy 2: We can find least common denominator(lcd) of both sides and multiplying both sides by that lcd to get rid denominators from both sides.

LCD of 42 and 7 is 42.

Therefore, multiplying both sides by 42, we get

42\times \frac{x}{42}=42\times\frac{3}{7}

x = 6 * 3

<h3>x = 18.</h3>
4 0
2 years ago
A certain book is sold in a paperback version for 4.75 or in a hardcover versoin for 11.50, If a copy of the book is being purch
mote1985 [20]

Answer:

$135

Step-by-step explanation:

Paperback=$4.75

Hardcover=$11.50

Multiply 4.75 and 20=95

Multiply 11.50 and 20=230

Subtract 230 and 95=135

so it would be $135

4 0
3 years ago
Kim and Stacy like to make necklaces. Kim has made 25 necklaces, and Stacy has made t necklaces. They have made a total of 57 ne
Alecsey [184]
Your equation would be t +25=57 because we don’t know how many necklaces Stacy made so we use T to plug it in and solve
6 0
3 years ago
Read 2 more answers
A Web music store offers two versions of a popular song. The size of the standard version is 2.4 megabytes (MB). The size of the
ANEK [815]

Answer:

50.mb

Step-by-step explanation:

7 0
3 years ago
. A special safe lets you choose from 9 symbols for a 3-symbol-long pass code. You may enter a symbol any number of times. How m
Lady_Fox [76]

The question is an illustration of combination and there are 729 potential pass codes available

<h3>How to determine the number of potential pass codes?</h3>

The given parameters are

Symbols available = 9

Length of pass code = 3

From the question, we understand that a symbol may be entered any number of times.

This means that each of the 9 available symbols can be used three times

So, the number of potential pass codes is

Passcodes = 9 * 9 * 9

Evaluate the product

Passcodes = 729

Hence, there are 729 potential pass codes available

Read more about combination at:

brainly.com/question/11732255

#SPJ1

4 0
1 year ago
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