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Dmitry_Shevchenko [17]
2 years ago
7

What is the range of the data?

Mathematics
1 answer:
PilotLPTM [1.2K]2 years ago
6 0

Answer:

is the difference between highest and lowest values.

Step-by-step explanation:

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GEOMETRY PLEASE HELP
marysya [2.9K]

Answer:

see explanation

Step-by-step explanation:

(5)

Since ∠EBA = 90° then ∠ABD = 90° ( straight angle ) and

∠ABC + ∠CBD = ∠ABD, that is

2x + 3x - 10 = 90, simplifying

5x - 10 = 90 ( add 10 to both sides )

5x = 100 ( divide both sides by 5 )

x = 20, thus

∠ABC = 2x = 2 × 20 = 40°

∠CBD = 3x - 10 = (3 × 20) - 10 = 60 - 10 = 50°

(6)

4x - 18 = 3x + 7 ( vertical angles are congruent )

Subtract 3x from both sides

x - 18 = 7 ( add 18 to both sides )

x = 25

7y = 5y + 28 ( vertical angles are congruent )

Subtract 5y from both sides

2y = 28 ( divide both sides by 2 )

y = 14

7 0
2 years ago
What is the lowest term for 5/8+1/2=
irakobra [83]

Answer:

5/8+1/2=9/8 or 1 1/8

Step-by-step explanation:

1/2 x 4 (top and bottom)= 4/8

5/8 + 4/8 = 9/8

3 0
2 years ago
Read 2 more answers
Find the sum <br> 3n/ n^2 +4n+4 + 7/n^2+6n+8
Marianna [84]

Answer:

1=1=1=1=1=1=1=1=1=1=1=1=1=1=1=1=1=1=1=1=1=1-1=0

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Y=-1/2x+10x what is the height of the arch at the turning point
lozanna [386]

your equation is linear, so there isn't any arch

6 0
3 years ago
Can someone help me with this and show their work and how they found the answer?
Semenov [28]

Answer:

2kg

Step-by-step explanation:

Let the sum of the other 2 bricks be R. Given that the heaviest brick weighs 2/3 times as much as the other 2 bricks in total, then the weight of the heaviest brick H in terms of the weight of the other 2 will be

H = 2/3 * R

= 2R/3

Given that the 3 bricks weigh 5kg in total then,

2R/3 + R = 5

Multiply through the equation by 3

2R + 3R = 15

5R = 15

Divide both sides by 5

R = 15/5

= 3

The weight of the heaviest brick is 2R/3. Since R = 3, the heaviest block weighs

= 2 * 3/3

= 2kg

4 0
3 years ago
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