Let the number of reserved tickets = x
Let the number of lawn seats = y
Constraint functions:
Maximum capacity means 
For concert to be held 
means 
Objective functions :
Maximum profit equation p = 65x +40y
Intersection points :
(10000,10000) (20000,0)(2500,2500)(5000,0)
p at (10000,10000) = 65(10000) + 40(10000) = $1050000
p at (20000,0) = 65(20000) + 40(0) = $1300000
p at (2500,2500) = 65(2500) + 40(2500) = $262500
p at (5000,0) = 65(5000) + 40(0) = $325000
Hence maximum profit occurs when all 20000 reserved seats are sold and the profit is $1300000
Please find attached the graph of it.
Answer:
y = -3/4x + 4
Step-by-step explanation:
y = mx + b
-2 = (-3/4)(8) + b
-2 = -6 + b
4 = b
y = -3/4x + 4
Answer:
66 minutes, or 1 hour and 6 minutes.
Step-by-step explanation:
let us first do the rectangular aquarium:
8 x 10 = 80
80 x 14 = 1120
now the second box
23 x 25 = 575
575 x 33 = 18975
we can divide the boxes volume:
18975/575 = 33
so all we have to do is times 33 by 2 which equals:
66 minutes, or 1 hour and 6 minutes.
The solution to a system of equations is the point where the 2 lines of a graph cross each other.
On the pictured graph, the lines cross each other at x = -6 and Y = -2.
The answer would be (-6,-2)
