Answer:
The answer is R0, 90° and (x , y) → (-y , x) ⇒1st and 4th
Step-by-step explanation:
* Lets revise the rotation rules
- If point (x , y) rotated about the origin by angle 90° anti-clock wise
(+90° or -270°)
∴ Its image is (-y , x)
- If point (x , y) rotated about the origin by angle 90° clock wise
(-90° or +270°)
∴ Its image is (y , -x)
- If point (x , y) rotated about the origin by angle 180°
(+180° or -180°)
∴ Its image is (-x , -y)
* There is no difference between rotating 180° clockwise or
anti-clockwise around the origin
* Lets solve the problem
∵ Δ XYZ has vertices⇒ X (0 , 0) , Y (0 , -2) , Z (-2 , -2)
∵ Δ X'Y'Z' has vertices X' (0 , 0) , Y' (2 , 0) , Z' (2 , -2)
* From them
# Y = (0 , -2) and Y' = (2 , 0), that means the image is (-y , x)
# Z = (-2 , -2) and Z' = (2 , -2), that means the image is (-y , x)
∴ The rotation is around the origin with angle 90° anti-clockwise
<em>V.I.N: </em>Anti-clock wise means positive angle , clockwise means
negative angle (90° means anti-clockwise , -90° means clockwise)
∴ The answer is: R0, 90° and (x , y) → (-y , x)
