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agasfer [191]
3 years ago
11

One hundred clothing stores go out of business. This will

Mathematics
2 answers:
FrozenT [24]3 years ago
5 0
Increase because there aren’t many clothes now
crimeas [40]3 years ago
4 0

Answer:

A increase, because less stores means more people going to the other ones, which means more money for the owners, which means if they raise the proces, people still need cloths sothey will still buy

Step-by-step explanation:

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Which equation finds the volume of a cube with a side length of 2n6 units?
Xelga [282]

Answer:

Volume of the cube = (2n6)³

Step-by-step explanation:

Volume of a cube = L*B*H

Volume of a cube= L*L*L=L³ (since all the sides of the cube are equal.

Volume of the cube = (2n6)³

7 0
2 years ago
What is the solution to this system of equations
statuscvo [17]
The answer to the question is b

6 0
3 years ago
State the necessary value of nn that will make each statement true.<br> 0.0004 × 0.002 = 8 × 10^n
vodka [1.7K]

Answer:

-7 = n

Step-by-step explanation:

0,002 \times 0,0004 = 0,0000008

0,0000008 = 8 \times {10}^{-7}

* You must make sure that you have seven zeros in your decimal.

I am joyous to assist you anytime.

6 0
2 years ago
Consider two functions: g(x)=−x2−6x and the quadratic function ​f(x)​ shown in the table.
S_A_V [24]

Answer:

Hence average rate of change is greater for f(x) in (0,3).

Yes. f(x) is greater than g(x) in the interval (0,3)

Yes. g(3) <f(3)


Step-by-step explanation:

To find average rate of change of f and g in (0,3)

f(3)-f(0)/3 = (9-0)/3 =3

g(3) = -9-18 = -27

g(0) = 0

Rate of change in(0,3) of g(x) = -27/3 =-9

Hence average rate of change is greater for f(x) in (0,3)

---

Both f and g have intercepts of y as 0

Hence both are equal.

3) Yes. f(x) is greater than g(x) in the interval (0,3)

Because g(x) <0 for all x in (0,3) while f(x) >0

4) g(3)= -9-18=-27 <f(3)



5 0
3 years ago
Read 2 more answers
Suppose that a simulation with a six-sided number cube provided these results during testing.
lyudmila [28]
Theoretical probability:
1 ... (16 and 2/3) %
2 ... (16 and 2/3) %
3 ... (16 and 2/3) %
4 ... (16 and 2/3) %
5 ... (16 and 2/3) %
6 ... (16 and 2/3) %

Experimental results:
1 ... 18
2 ... 16
3 ... 16
4 ... 17
5 ... 16
6 ... 17

The total number of rolls in the experiment was

         (18 + 16 + 16 + 17 + 16 + 17)  =  100

so the expected frequency for each outcome was 16-2/3 times,
and the SIMULATION probabilities were

1 ... 18%
2 ... 16%
3 ... 16%
4 ... 17%
5 ... 16%
6 ... 17%

To me, this looks fantastically close.  The cube
could hardly be more fair than it actually is.










8 0
3 years ago
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