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harina [27]
3 years ago
8

4 points: A,B,C and D are marked in order on a line such that AB:AC = 3:5 and BD:CD= 7:2. If CD is 10cm long, find the length of

AB.
Mathematics
1 answer:
Jlenok [28]3 years ago
4 0
<span><span>ab:ac=3:5
bd:cd=7:2
if cd is 5 cm then cd=2:5 then ab=3:x

2:5=3:x
15=2x
x=15/2
x=7.5 cm</span><span>
Happy studying! ^_^</span></span>
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If the value of third order determinant is 11. Then what is the value of the determinant formed by its cofactors.
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Answer:

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Step-by-step explanation:

third order determinant = determinant of 3×3 matrix A

given ∣A∣=11

det (cofactor matrix of A) =set (transpare of cofactor amtrix of A) (transpare does not change the det)

=det(adjacent of A)

{det (cofactor matrix of A)}  ^2  = {det (adjacent of A)} ^2

 

(Using for an n×n det (cofactor matrix of A)=det (A)^n−1 )

we get

det (cofactor matrix of A)^2  = {det(A)  ^3−1 }^2

 

=(11)^2×2  = 11^4

 =146.41

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