Answer: The cost of one sandwich is $4.25 and the cost of one cup of coffee is $2.25.
Step-by-step explanation:
Let x be the cost of one sandwich and y be the cost of one cup of coffee.
By considering the given situation, we have the following equations :-
Multiply 2 on both sides of equation (2) , we get
Subtract equation (1) from equation (3), we get
Put value of y in (1), we get
Hence, the cost of one sandwich is $4.25 and the cost of one cup of coffee is $2.25.
For this you can just use a calculator and divide 2587.5 by 1150.
You should get $2.25 for the unit price. Hope this helped ^-^
Hi! for x, you need to do 2x-8 = x+17 and solve, because since b is the midpoint, ab and bc would be congruent.
2x-8 = x+17
1x-8 = 17
1x = 25
x = 25
in order to find ab, you plug in the x into the expression.
ab = 2x-8
ab = 2(25)-8
ab = 42
do the same for bc:
bc = x + 17
bc = 25 + 17
bc = 42
and for ac, combine the two expressions and plug in the value for x.
ac = ab + bc
ac = 2x-8 + x+17
ac = 2(25)-8 + 25+17
ac = 84
i hope this helped! have a good day/night :)
The answer is the first one
From what I think;
8.216secs - 1 wheel; 3.652- 1 hood
for I toy car with a wheel and hood the total time is 8.216+ 3.652 = 11.868secs
let x secs be the total time taken to put a wheel and hood for 42 cars
x secs = 42 cars × the total time for one car
x secs = 42× 11.868
x secs= 498.456 secs
