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Svetach [21]
3 years ago
13

ΔABC is rotated 100° counterclockwise about point P to create ΔA′B′C′. What is m∠C'A'B' ?

Mathematics
2 answers:
grin007 [14]3 years ago
5 0
Base on my calculation and also by the sue of the data you give where as the  triangle ABC is rotated by 100 counter clockwise about point P to create triangle A'B'C' the possible value of angle C'A'B is 70 degrees. I hope you are satisfied with my answer and feel free to ask for more 
Elanso [62]3 years ago
3 0
I believe the answer is 70! :) hope it's right!
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<h3><u>Answer</u> :</h3>

\sf \dashrightarrow \dfrac{22}{7} \div \dfrac{22}{7}

\sf \dashrightarrow \dfrac{22}{7} \times \dfrac{7}{22}

\sf \dashrightarrow \dfrac{\cancel{22}}{\cancel{7}} \times \dfrac{\cancel{7}}{\cancel{22}}

\sf \dashrightarrow 1 \times 1

\sf \dashrightarrow 1

<h3>Hence, answer is 1.</h3>
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