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yarga [219]
3 years ago
6

kate has walk 6000 steps each day for one week her weekly steps Target is to walk 56,000 steps what percent on her weekly steps

target did she achieve
Mathematics
2 answers:
Lynna [10]3 years ago
6 0

Answer:

She reached 75% of her goal!

Step-by-step explanation:

first i find out how many steps she took in total:

6000 x 7 = 42000

then i set up proportions so i can cross multiply

\frac{42000}{50000}= \frac{x}{100}

42000 x 100 = 4200000

4200000 / 56000 = 75

icang [17]3 years ago
3 0

Answer:

the answer is 75%

Step-by-step explanation:

6000 \times 7 = 42000

\frac{42000}{56000}  \times 100 = 75

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Line segment RS is graphed with its end points at (1, 3) and (7, 11) If RS is dilated by a
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For the answer to the question above, <span>what is the combined length of
the original line segment and its dilated image?
</span>RS = 10 
image R'S' = 20 
---> 10+20=30
I hope my answer helped you. Feel free to ask more questions. have a nice day!
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2 years ago
What is the diameter of a hemisphere with a volume of 5403 ft", to the nearest tenth<br> of a foot?
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3 years ago
Is :<br> -.6 <br> IRRATIONAL?<br> yes<br> or <br> no
Anastaziya [24]

Answer:

I would say -6 is an irrational number.

Step-by-step explanation:

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7 0
3 years ago
Read 2 more answers
Q: In an examination 14% of the students failed and 559 students passed. Find
topjm [15]
100% - 14% = 86%
86% of what gives you 559
559 * 100 = 55,900/86 = 650
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7 0
3 years ago
a math teacher claims that she has developed a review course that increases the score of students on the math portion of a colle
madam [21]

Answer:

A.

H_0: \mu\leq514\\\\H_1: \mu>514

B. Z=2.255. P=0.01207.

C. Although it is not big difference, it is an improvement that has evidence. The scores are expected to be higher in average than without the review course.

D. P(z>0.94)=0.1736

Step-by-step explanation:

<em>A. state the null and alternative hypotheses.</em>

The null hypothesis states that the review course has no effect, so the scores are still the same. The alternative hypothesis states that the review course increase the score.

H_0: \mu\leq514\\\\H_1: \mu>514

B. test the hypothesis at the a=.10 level of confidence. is a mean math score of 520 significantly higher than 514? find the test statistic, find P-value. is the sample statistic significantly higher?

The test statistic Z can be calculated as

Z=\frac{M-\mu}{s/\sqrt{N}} =\frac{520-514}{119/\sqrt{2000}}=\frac{6}{2.661}=2.255

The P-value of z=2.255 is P=0.01207.

The P-value is smaller than the significance level, so the effect is significant. The null hypothesis is rejected.

Then we can conclude that the score of 520 is significantly higher than 514, in this case, specially because the big sample size.

C.​ do you think that a mean math score of 520 vs 514 will affect the decision of a school admissions adminstrator? in other words does the increase in the score have any practical significance?

Although it is not big difference, it is an improvement that has evidence. The scores are expected to be higher in average than without the review course.

D. test the hypothesis at the a=.10 level of confidence with n=350 students. assume that the sample mean is still 520 and the sample standard deviation is still 119. is a sample mean of 520 significantly more than 514? find test statistic, find p value, is the sample mean statisically significantly higher? what do you conclude about the impact of large samples on the p-value?

In this case, the z-value is

Z=\frac{520-514}{s/\sqrt{n}} =\frac{6}{119/\sqrt{350}} =\frac{6}{6.36} =0.94\\\\P(z>0.94)=0.1736>\alpha

In this case, the P-value is greater than the significance level, so there is no evidence that the review course is increasing the scores.

The sample size gives robustness to the results of the sample. A large sample is more representative of the population than a smaller sample. A little difference, as 520 from 514, but in a big sample leads to a more strong evidence of a change in the mean score.

Large samples give more extreme values of z, so P-values that are smaller and therefore tend to be smaller than the significance level.

8 0
2 years ago
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