Answer:
Time required by Machine B to create a widget = 4 hours
Step-by-step explanation:
Time taken by Machine A ( 
) = 3 hours
Time taken by Machine B ( 
)= x hours
Time taken by both machines by working together = 12 hours
The time required to both machines by working together to finish a task is given by the formula = 
Put the values in above formula we get
⇒ T = 
⇒ 12 =
⇒ 36 + 12 x = 3 x
⇒ x = - 4 hours
This is the time required by Machine B to create a widget.
This question is Incomplete
Complete Question
Researchers recorded the speed of ants on trails in their natural environments. The ants studied, Leptogenys processionalis, all have the same body size in their adult phase, which made it easy to measure speeds in units of body lengths per second (bl/s). The researchers found that, when traffic is light and not congested, ant speeds vary roughly Normally, with mean 6.20 bl/s and standard deviation 1.58 bl/s. (a) What is the probability that an ant's speed in light traffic is faster than 5 bl/s? You may find Table B useful. (Enter your answer rounded to four decimal places.)
Answer:
0.7762
Step-by-step explanation:
We solve using z score formula
z = (x-μ)/σ, where
x is the raw score
μ is the population mean
σ is the population standard deviation.
Population mean = 6.20 bl/s
Standard deviation = 1.58 bl/s.
x = 5 bl/s
z = 5 - 6.20/1.58
z = -0.75949
The probability that an ant's speed in light traffic is faster than 5 bl/s is P( x > 5)
Probability value from Z-Table:
P(x<5) = 0.22378
P(x>5) = 1 - P(x<5)
= 1 - 22378
= 0.77622
Approximately to 4 decimal places = 0.7762
The probability that an ant's speed in light traffic is faster than 5 bl/s is 0.7762
Is it 57? ...............................
Answer:
16
Step-by-step explanation:
The common ratio is 36/54 = 2/3.
So the next term is 2/3 (24) = 16.
