Answer:
48 square units
Step-by-step explanation:
Let the length of the rectangle be x units.
By Pythagoras theorem:
![x = \sqrt{ {10}^{2} - {6}^{2} } \\ x = \sqrt{ 100 - 36 } \\ x = \sqrt{64} \\ x = 8 \: units \\](https://tex.z-dn.net/?f=x%20%3D%20%20%5Csqrt%7B%20%7B10%7D%5E%7B2%7D%20%20-%20%20%7B6%7D%5E%7B2%7D%20%7D%20%20%5C%5C%20x%20%3D%20%20%5Csqrt%7B%20100%20%20-%2036%20%7D%20%20%5C%5C%20x%20%3D%20%20%5Csqrt%7B64%7D%20%20%5C%5C%20x%20%3D%208%20%5C%3A%20units%20%5C%5C%20)
Length of rectangle = 8 units
Area of rectangle
= Length * width
= 8 * 6
= 48 square units
The hypotenuse is always the longest side of a triangle and seeing that it is 8, X has to be something smaller so X is likely 4.
C. x = 7
1 + 3 * x = 22
1 + 3x = 22
Subtract 1 from both sides.
3x = 21
Divide both sides by 3.
x = 7
First, you have to add 16 to both sides because it's the opposite of subtracting.
h-16<24
+16 +16
-16+16 will cancel each other out.
24+16=40
So, h<40
Or in other words, h is smaller than 40.
Hope it helps ^_^