All categories

3 years ago

The sum of the two prime numbers between 110 and 130 is

1 answer:

7 0

Prime numbers are those numbers which have only two factors, 1 and the number itself . For e.g. 3,5,7,11 etc are all prime numbers.

Between 110 and 130 we have a total of two prime numbers which are 113 and 127, since both have only two factors .

And sum of 113 and 127 is

$113+127= 240$

So the required answer is 240 .

You might be interested in

1. Solve for the area of the figure below.

wariber [46]

Answer:

Step-by-step explanation:

7 0

2 years ago

In the function f(t) = sin(t), what is the effect of multiplying t by a coefficient of 2?

liubo4ka [24]

Answer:

"changes the period to pi"

Step-by-step explanation:

f(t) = Sin(t),

Here, t is the period, by definition.

Multiply t by a number that is GREATER THAN 1, makes the period shorter and compressed.

Multiplying t by a number that is between 0 and 1 makes the period expanded.

For the first, if we multiply the period by a, the period becomes $\frac{2\pi}{a}$

Since the problem tells us to multiply by 2, we know the period becomes compressed and becomes :

$\frac{2\pi}{2}=\pi$

Third answer choice is right.

5 0

2 years ago

A tablet is on sale for 30% off. the regular price is $185. how much money will you save?

Burka [1]

Answer:

185×30÷100=55.5

HERES YOUR answer

8 0

3 years ago

Circle B has a center at point (0, 2) and a point W on the circle at (3, 3). Which equation represents a line that is tangent to

Solnce55 [7]

According to the given information, the equation represents a line that is tangent to the circle and goes through the point W is given by:

y = -x + 6.

<h3>What is the equation of the circle?</h3>

The equation of a circle of center $(x_0,y_0)$ and radius r is given by:

$(x - x_0)^2 + (y - y_0)^2 = r^2$

In this problem, we have that the center is at point (0,2), hence:

$x^2 + (y - 2)^2 = r^2$

It goes through point (3,3), hence:

$3^2 + (3 - 2)^2 = r^2$

$r^2 = 10$

Hence, the equation is:

$x^2 + (y - 2)^2 = 10$

<h3>What is the equation of the tangent line at point W?</h3>

It is given by:

$y - y(0) = \frac{dy}{dx}|_{W}(x - x(0))$

Applying implicit differentiation, we have that:

$2x + 2y\frac{dy}{dy} = 0$

$\frac{dy}{dx} = -\frac{x}{y}$

Point W(3,3), hence:

$(x_0, y_0) = (3,3)$

$\frac{dy}{dx} = -\frac{3}{3} = -1$

Hence the equation is:

y - 3 = -(x - 3).

y = -x + 6.

More can be learned about the equation of a tangent line at brainly.com/question/8174665

5 0

2 years ago

The number of square feet per house is normally distributed with a population standard deviation of 154 square feet and an unkno

11111nata11111 [884]

Answer: (1500.66,1599.34)

Step-by-step explanation:

Confidence interval for population mean:

$\overline{x}\pm z^*\dfrac{\sigma}{\sqrt{n}}$

,where $\overline{x}$ = Sample mean , n= Sample size, z* = critical two tailed z-value , $\sigma$ = population standard deviation.

As per given , we have

n= 16

$\sigma = 154$ square feet

$\overline{x}= 1550$ square feet

$\alpha= 1-0.80 = 0.20$

Critical z-value = $z_{\alpha/2}=z_{0.2/2}=z_{0.1}=1.2815$

Confidence interval for population mean:

$1550\pm (1.2815)\dfrac{154}{\sqrt{16}}\\\\ = 1550\pm (1.2815)\dfrac{154}{4}\\\\= 1550\pm 49.33775\\\\ =(1550-49.33775,\ 1550+49.33775)\\\\\approx (1500.66,\ 1599.34)$

Required confidence interval: (1500.66,1599.34)

6 0

2 years ago