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erma4kov [3.2K]
3 years ago
9

What is the slope of the line if the equation is 5x-3y=9

Mathematics
1 answer:
allochka39001 [22]3 years ago
5 0

Answer:

Slope = 5/3

Step-by-step explanation:

5x - 3y = 9

Write in slope y-intercept form: y = mx +b

-3y = -5x + 9

Divide the whole equation by (-3)

\frac{-3y}{-3}=\frac{-5x}{-3}+\frac{9}{-3}\\\\y =\frac{5}{3}x- 3

Slope =5/3

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Answer:

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Step-by-step explanation:

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2 years ago
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Alenkasestr [34]

Answer:

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3 years ago
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Determine the area under the standard normal curve that lies to the left of (a) Z=081. (b) Z=0.43. (c) Z= -0.33. and (d) Z= 1.04
nasty-shy [4]

Using the normal distribution, the areas to the left are given as follows:

a) 0.7910.

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d) 0.8508.

<h3>Normal Probability Distribution</h3>

The z-score of a measure X of a normally distributed variable with mean \mu and standard deviation \sigma is given by:

Z = \frac{X - \mu}{\sigma}

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Hence:

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  • The area to the left of Z = 0.43 is of 0.6664.
  • The area to the left of Z = -0.33 is of 0.3707.
  • The area to the left of Z = 1.04 is of 0.8508.

More can be learned about the normal distribution at brainly.com/question/4079902

#SPJ1

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2 years ago
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