Answer:
25.9%
Step-by-step explanation:
Since, the actual dimensions of the cylinder is not given we can assume the some dimension to explain the problem
Let us assume the dimension of the cylinder be
radius= 3in
height= 5 in
The expression for the total surface area of a cylinder is
T. S. A. =2πrh+2πr^2
Let us plug in the values to to find TSA
T. S. A. =2×3.14×3×5+2×3.14×3^2
Solving we get
T. S. A. =94.26+56.556
T. S. A. =150.816 in^2
Now let us find the error
we know that error % is calculated as
%error= [actual value-expected value/expected value]×100
%error= [190 -150.816/150.816]×100
%error= [39.184/150.816]×100
%error= 0.259×100
%error= 25.9%
Answer:
58 seconds
Step-by-step explanation:
Given:
Initial mass of water = 1 kg
Specific energy = 2297 kJ/kg
Heat supplied by the stove = 20 kJ/s
Now,
Half water is to be vaporized i.e 0.5 kg
Thus, heat required for vaporizing 0.5 kg water = mass × specific heat
or
heat required for vaporizing 0.5 kg water = 0.5 × 2297 = 1148.5 kJ
Therefore,
time taken to provide the required heat = 
or
time taken to provide the required heat = 
or
time taken to provide the required heat = 57.425 ≈ 58 seconds
Multiples of 2: 2, 4, 6, 8, 10, 12, 14, 16, 18, 20, 22, 24, 26, 28, 30, 32, 34, 36, 38, 40, 42, 44, 46, 48, 50, 52, 54, 56, 58, 60, 62, 64, 66, ...
Multiples of 6: 6, 12, 18, 24, 36, 42, 48, 54, 60, 66, ...
Multiples of 11: 11, 22, 33, 44, 55, 66, ...
The lcm of 2, 6, and 11 is 66
