<span>Assume that,
x^2+4x-5 = 0 .......(1)
Then,
x^2+4x-5 = 0
x^2+5x-1x-5 =0
x(x+5)-1(x+5) = 0
(x+5) (x-1) = 0
We get x=-5 and x=1
Sub x=-5 in equ (1)
(-5)^2+4(5)-5 = 0
-25+20-5 = 0
-25+25= 0
0 = 0
Sub x=1 in equ (1)
(1)^2+4(1)-5 = 0
1+4-5 = 0
5-5 = 0
0 = 0
Therefore x value is -5 and 1</span>
Answer:
is not a logarithmic function because the base is equal to 1.
Step-by-step explanation:
A logarithmic function is of the form: 
For a logarithmic function to exist, we must fulfill certain conditions. The conditions are
i. The base, 
, is greater than 0. 
ii. The base, , is not equal to 1. 
iii. 
must be greater than 0. 
Now, if we observe all the choices given, we conclude that the third choice is correct as the base there is 1. If base is equal to 1, then it violates the definition of logarithmic functions. So, the correct choice is:
is not a logarithmic function because the base is equal to 1.
No, it is an irrational number. It repeats
No, it is an irrational number because it does not terminate/end
90/36 is 2.5, so the Baker needs to make 2.5 batches of cookies
2.5 batches of cookies x 2.25 cups of flour
is 5.625 cups of flour
which is 5 5/8 cups of flour
Answer:
iters and millimets
Step-by-step explanation:
Ur welcome:)
