Tan (Ф/2)=⁺₋√[(1-cosФ)/(1+cosФ)]
if π<Ф<3π/2;
then, Where is Ф/2??
π/2<Ф/2<3π/4; therefore Ф/2 is in the second quadrant; then tan (Ф/2) will have a negative value.
tan(Ф/2)=-√[(1-cosФ)/(1+cosФ)]
Now, we have to find the value of cos Ф.
tan (Ф)=4/3
1+tan²Ф=sec²Ф
1+(4/3)²=sec²Ф
sec²Ф=1+16/9
sec²Ф=(9+16)/9
sec²Ф=25/9
sec Ф=-√(25/9) (sec²Ф will have a negative value, because Ф is in the sec Ф=-5/3 third quadrant).
cos Ф=1/sec Ф
cos Ф=1/(-5/3)
cos Ф=-3/5
Therefore:
tan(Ф/2)=-√[(1-cosФ)/(1+cosФ)]
tan(Ф/2)=-√[(1+3/5)/(1-3/5)]
tan(Ф/2)=-√[(8/5)/(2/5)]
tan(Ф/2)=-√4
tan(Ф/2)=-2
Answer: tan (Ф/2)=-2; when tan (Ф)=4/3
P should equal 3. hope this helps.
Given:
In 2010, the population of a town = 2000
Every year, it increase by 1.5%
To find the equation P(t) which represents the population of this town t years from 2010.
Formula
If a be the original population of a town and it increases by b% every year, after t year the population will be
Now,
Taking, a =2000, b = 1.5 we get,
or, 
Hence,
The population of this town t years from 2010 P(t) = 
, Option D.
Answer:
it is (6)(10)
Step-by-step explanation:
I just took the edgenuity test so I know
Answer:
Step-by-step explanation:
6x+2=9x-1 x=1
6(1)+2=9(1)-1
6+2=9-1
8=8
Hope this helps :)
