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myrzilka [38]
3 years ago
6

20 POINTS!!! I GIVE BRAINLIEST PLEASE HELP!!!!A circle with a circumference of approximately 15.71 inches drawn inside a square,

just touching the sides of the square. Explain how to determine the length of one side of the square.
Mathematics
1 answer:
Oksi-84 [34.3K]3 years ago
3 0

answer:

5.002 inches

step-by-step explanation:

  • find the diameter of the circle
  • the diameter is the side length of the square since the sides of it are touching the circle

c = 2πr

  • c stands for circumference
  • π stands for pi (or 3.14)
  • r stands for radius

- plug in the values given to find the diameter

c = 2πr

15.71 = 2(3.14)r

15.71 = 6.28r

r = 2.501 (rounded or estimated)

  • now that we have the radius, we can find the diameter by multiplying by 2, since diameter is two times bigger than the radius

diameter = 5.002 (estimated)

  • now, that will be the side length because the diameter = the side length
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Answer:

t=\frac{51.6-48}{\frac{1.1}{\sqrt{10}}}=10.349      

p_v =P(t_9>10.349)=1.34x10^{-6}  

If we compare the p value and the significance level given for example \alpha=0.05 we see that p_v so we can conclude that we reject the null hypothesis, and the the actual mean is significantly higher than 48 MPa at 5% of significance.

Step-by-step explanation:

1) Data given and notation      

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n=10 sample size      

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\alpha=0.05 represent the significance level for the hypothesis test.    

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p_v represent the p value for the test (variable of interest)  

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t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Calculate the statistic      

We can replace in formula (1) the info given like this:      

t=\frac{51.6-48}{\frac{1.1}{\sqrt{10}}}=10.349      

Calculate the P-value      

First we find the degrees of freedom:

df=n-1=10-1=9

Since is a one-side upper test the p value would be:      

p_v =P(t_9>10.349)=1.34x10^{-6}  

Conclusion      

If we compare the p value and the significance level given for example \alpha=0.05 we see that p_v so we can conclude that we reject the null hypothesis, and the the actual mean is significantly higher than 48 MPa at 5% of significance.        

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