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3 years ago

PLEASE HELP!!!! and show your work

Mathematics

1 answer:

Goryan [66]3 years ago

4 0

The answer would be

4.41

my work is in the image below

hope this helps :)

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Help ASAP please!!! First answer and correct answer gets the brain...

EleoNora [17]

Answer:

U = 40/3

Hope this helps :-)

3 0

3 years ago

Jacob wrote the expression shown. 10 + 5 + 4(72-6) What do these parentheses indicate in the expression? F Divide 10 by 5 before

icang [17]

You would multiply 4 by 72 then u multiply 4 * -6 then after that you would add 15

7 0

2 years ago

Of the students in your class, 12% are left-handed. What fraction of the students are left-handed? Are there more right-handed o

kvv77 [185]

The left-handed students
12% are left handed, percent means per hundred. Change percent into per 100.
12% = $\dfrac{12}{100}$

Then simplify the fraction by dividing the numerator and denominator by 4
$\dfrac{12}{100}$
= $\dfrac{12:4}{100:4}$
= $\dfrac{3}{25}$
This is the fraction showing the proportion of the left-handed students

The right-handed students
Determine the fraction showing the proportion of the right-handed students
1 - the left-handed
= 1 - $\dfrac{3}{25}$

Equalize the denominator to 25
$\dfrac{25}{25} - \dfrac{3}{25}$

Simplify
$\dfrac{21}{25}$
This is the proportion of the right-handed students

Are there more right-handed or left-handed students?
There are more right-handed students than the left-handed students, because 21/25 is more than 3/25

4 0

3 years ago

(a)

Allisa [31]

Answer:

320,000

Step-by-step explanation:

4 0

2 years ago

Five state officials are listed to the right. a. List the 10 possible samples (without replacement) of size 3 that can be obtai

mart [117]

Answer:

All possible are:

(G,L,S)

(G,L,R)

(G,L,P)

(G,S,R)

(G,S,P)

(G,R,P)

(L,S,R)

(L,S,P)

(S,R,P)

{L,R,P)

Probability of 1st/2nd/10th sample = 1/10

Step-by-step explanation:

All the possible combinations of the 3 size samples from a 5 size population have been listed without repetition.

Total Numbers of Samples = 10

To find the probability of finding the first sample from random sampling procedure,

Probability = Number of desired outcomes/ Total number of outcomes

Where Number of desired outcome is 1 and total number of outcomes is 10.

Probability = 1/10

Similarly, to find 2nd sample or 10th sample, the number of desired outcomes is same i.e 1, hecne the probability remains the same i.e 1/10

7 0

3 years ago