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Liula [17]
3 years ago
14

PLEASE HELP!!!! and show your work

Mathematics
1 answer:
Goryan [66]3 years ago
4 0
The answer would be 

4.41

my work is in the image below 

hope this helps :) 

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Help ASAP please!!!<br> First answer and correct answer gets the brain...
EleoNora [17]

Answer:

<u><em>U = 40/3</em></u>

<u><em>Hope this helps :-)</em></u>


3 0
3 years ago
Jacob wrote the expression shown. 10 + 5 + 4(72-6) What do these parentheses indicate in the expression? F Divide 10 by 5 before
icang [17]
You would multiply 4 by 72 then u multiply 4 * -6 then after that you would add 15
7 0
2 years ago
Of the students in your class, 12% are left-handed. What fraction of the students are left-handed? Are there more right-handed o
kvv77 [185]
The left-handed students
12% are left handed, percent means per hundred. Change percent into per 100.
12% = \dfrac{12}{100}

Then simplify the fraction by dividing the numerator and denominator by 4
\dfrac{12}{100}
= \dfrac{12:4}{100:4}
= \dfrac{3}{25}
This is the fraction showing the proportion of the left-handed students

The right-handed students
Determine the fraction showing the proportion of the right-handed students
1 - the left-handed
= 1 - \dfrac{3}{25}

Equalize the denominator to 25
\dfrac{25}{25} - \dfrac{3}{25}

Simplify
\dfrac{21}{25}
This is the proportion of the right-handed students

<span>Are there more right-handed or left-handed students?
There are more right-handed students than the left-handed students, because 21/25 is more than 3/25</span>
4 0
3 years ago
(a)
Allisa [31]

Answer:

320,000

Step-by-step explanation:

4 0
2 years ago
Five state officials are listed to the right. a. List the 10 possible samples​ (without replacement) of size 3 that can be obtai
mart [117]

Answer:

All possible are:

(G,L,S)

(G,L,R)

(G,L,P)

(G,S,R)

(G,S,P)

(G,R,P)

(L,S,R)

(L,S,P)

(S,R,P)

{L,R,P)

Probability of 1st/2nd/10th sample = 1/10

Step-by-step explanation:

All the possible combinations of the 3 size samples from a 5 size population have been listed without repetition.

Total Numbers of Samples = 10

To find the probability of finding the first sample from random sampling procedure,

Probability = Number of desired outcomes/ Total number of outcomes

Where Number of desired outcome is 1 and total number of outcomes is 10.

Probability = 1/10

Similarly, to find 2nd sample or 10th sample, the number of desired outcomes is same i.e 1, hecne the probability remains the same i.e 1/10

7 0
3 years ago
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