Answer:
<u><em>U = 40/3</em></u>
<u><em>Hope this helps :-)</em></u>
You would multiply 4 by 72 then u multiply 4 * -6 then after that you would add 15
The left-handed students12% are left handed, percent means per hundred. Change percent into per 100.
12% =

Then simplify the fraction by dividing the numerator and denominator by 4

=

=

This is the fraction showing the proportion of the left-handed students
The right-handed studentsDetermine the fraction showing the proportion of the right-handed students
1 - the left-handed
= 1 -

Equalize the denominator to 25

Simplify

This is the proportion of the right-handed students
<span>
Are there more right-handed or left-handed students?There are more right-handed students than the left-handed students, because 21/25 is more than 3/25</span>
Answer:
320,000
Step-by-step explanation:
Answer:
All possible are:
(G,L,S)
(G,L,R)
(G,L,P)
(G,S,R)
(G,S,P)
(G,R,P)
(L,S,R)
(L,S,P)
(S,R,P)
{L,R,P)
Probability of 1st/2nd/10th sample = 1/10
Step-by-step explanation:
All the possible combinations of the 3 size samples from a 5 size population have been listed without repetition.
Total Numbers of Samples = 10
To find the probability of finding the first sample from random sampling procedure,
Probability = Number of desired outcomes/ Total number of outcomes
Where Number of desired outcome is 1 and total number of outcomes is 10.
Probability = 1/10
Similarly, to find 2nd sample or 10th sample, the number of desired outcomes is same i.e 1, hecne the probability remains the same i.e 1/10