68 is the 22nd term of the following sequence.
<u>Step-by-step explanation:</u>
- The given sequence is with the same common difference between the two consecutive number in the series thus it is said to be the Arithmetic progression ( AP).
- For finding the nth term in the AP we have a formula tn = a + (n-1) × d
- Here a is the first term , n is the number of the term to be founded and d is the common difference between the two consecutive number in the series.
- Thus here tn = 5 + ( 22 - 1 ) × 3.
- On subtracting we get tn = 5 + (21 ) × 3
- On multiplying we get tn = 5 + 63
- After adding we get tn = 68. It is the 22nd term in the given series.
Answer:
am aorry
Step-by-step explanation:
awfully sorry but i cant
Answer:
-1/3
Step-by-step explanation:
hope this helps
Answer:
f. sqrt 7 meters
Step-by-step explanation:
we use Pythagoras' theorem here,
let the unknown side be x,
therefore,
=> 3² + x² = 4²
=> x² = 16 - 9
=> x = √7 m
Divide both sides by -2
two negatives make a positive and that's true so x = 16/2 so divide it
x = 8 because 2 x 8 = 16 and 2/16 = 8 so true.
Answer: x = 8.
