Given:
m(ar QT) = 220
m∠P = 54
To find:
The measure of arc RS.
Solution:
PQ and PT are secants intersect outside a circle.
<em>If two secants intersects outside a circle, then the measure of the angle formed is one-half the positive difference of the measures of the intercepted arcs.</em>


Multiply by 2 on both sides.


Subtract 220 from both sides.


Multiply by (-1) on both sides.


The measure of arc RS is 112.
Answer:
Option B.
.
Step-by-step explanation:
The given equation is kx - 4 = 9
We will add 4 on both the sides of the equation
kx - 4 +4 = 9 +4
kx = 13
Now we will divide by k on both the sides of the equation

Therefore Option B x = 13/k is the right answer.
Answer:
<em>No, he should have set the sum of ∠AED and ∠DEC equal to 180°, rather then setting ∠AED and ∠DEC equal to each other</em>
Step-by-step explanation:
Find the diagram attached
If line AC and BD intersects, then m<AED + m<DEC = 180 (sum of angle on a straight line is 180 degrees)
Given
m<AED = 16x+8
m<DEC = 76 degrees
16x + 8 + 76 = 180
16x + 84 = 180
16x = 180-84
16x = 96
x = 96/16
x = 6
Hence the value of x is 6
Hence the correct option is <em>No, he should have set the sum of ∠AED and ∠DEC equal to 180°, rather then setting ∠AED and ∠DEC equal to each other</em>
Answer:
y = 1/2x +6
Step-by-step explanation:
We have a point and a slope. Therefore we can use the point slope form to create a line
y-y1 = m(x-x1)
y-5 = 1/2(x--2)
y-5 = 1/2(x+2)
Distribute the 1/2
y-5 = 1/2x +1
Add 5 to each side
y-5+5 = 1/2x +1+5
y = 1/2x +6
This is in slope intercept form