The law of cosines states that, if
is the angle between sides b and c,

So, plugging our values, we have

This is equal to

Answer:
The given statement is true because the person they did their steps correctly
a) Locate a point C so that ABC is a right triangle with m ACB ∠ = ° 90 and the measure of one of the acute angles in the triangle is 45° .
b) Locate a point D so that ABD is a right triangle with m ADB ∠ = ° 90 and
the measure of one of the acute angles in the triangle is30° .
c) Locate a point E so that ABE is a right triangle with m AEB ∠ = ° 90 and
the measure of one of the acute angles in the triangle is15° .
d) Find the distance between point C and the midpoint of segment AB .
Repeat with points D and E.
e) Suppose F is a point on the graph so that ABF is a right triangle
withm AFB ∠ =° 90 . Make a conjecture about the point F.
Answer:
B
Step-by-step explanation:
![~~~2x^{16} - 32x^4\\\\ = 2x^4(x^{12} -16)\\\\=2x^4\left[(x^6)^2 - 4^2 \right]\\\\=2x^4(x^6 -4)(x^6 +4)~~~~~~~~~~~~~~~~~~;[a^2 -b^2 = (a+b)(a-b)]\\\\=2x^4\left[(x^3)^2 - 2^2\right] (x^6 +4)\\\\=2x^4(x^3 -2)(x^3 +2)(x^6 +4)](https://tex.z-dn.net/?f=~~~2x%5E%7B16%7D%20-%2032x%5E4%5C%5C%5C%5C%20%3D%202x%5E4%28x%5E%7B12%7D%20-16%29%5C%5C%5C%5C%3D2x%5E4%5Cleft%5B%28x%5E6%29%5E2%20-%204%5E2%20%5Cright%5D%5C%5C%5C%5C%3D2x%5E4%28x%5E6%20-4%29%28x%5E6%20%2B4%29~~~~~~~~~~~~~~~~~~%3B%5Ba%5E2%20-b%5E2%20%3D%20%28a%2Bb%29%28a-b%29%5D%5C%5C%5C%5C%3D2x%5E4%5Cleft%5B%28x%5E3%29%5E2%20-%202%5E2%5Cright%5D%20%28x%5E6%20%2B4%29%5C%5C%5C%5C%3D2x%5E4%28x%5E3%20-2%29%28x%5E3%20%2B2%29%28x%5E6%20%2B4%29)
For this case we must solve the following equation:

We apply distributive property on the right side of the equation:

We subtract 6y on both sides of the equation:

We subtract 6 from both sides of the equation:

Dividing by 6 on both sides of the equation:

So, the result is 
Answer:
