Click off the first one because 180 (Thea) < 225 (Eleanor). Then keep the second one and click the third and fourth one.
Answer:
x = - 
Step-by-step explanation:
To find f(g(x)) substitute x = g(x) into f(x), that is
f(g(x))
= f(x + 1)
= 2(x + 1)² ← expand using FOIL
= 2(x² + 2x + 1) ← distribute
= 2x² + 4x + 2
To find g(f(x)) substitute x = f(x) into g(x), that is
g(f(x))
= g(2x²)
= 2x² + 1
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Equating gives
2x² + 4x + 2 = 2x² + 1 ( subtract 2x² + 1 from both sides )
4x + 1 = 0 ( subtract 1 from both sides )
4x = - 1 ( divide both sides by 4 )
x = -
Answer:
Since each bag has 9strawberries and lemon she gives out 10 strawberries and lemon so she remains with 9 and a quarter bags .
Step-by-step explanation:
Remember each bag contains 9 so she has to pick either one strawberry or a lemon so in the 9th bag she remains with 8 candies.
Answers:
x = -8/5 or x = 8/5
Sum of the first ten terms where all terms are positive = 4092
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Explanation:
r = common ratio
- first term = 4
- second term = (first term)*(common ratio) = 4r
- third term = (second term)*(common ratio) = (4r)*r = 4r^2
The first three terms are: 4, 4r, 4r^2
We're given that the sequence is: 4, 5x, 16
Therefore, we have these two equations
Solve the second equation for r and you should find that r = -2 or r = 2 are the only possible solutions. If r = -2, then 5x = 4r solves to x = -8/5. If r = 2, then 5x = 4r solves to x = 8/5.
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To find the sum of the first n terms, we use this geometric series formula
Sn = a*(1 - r^n)/(1 - r)
We have
- a = 4 = first term
- r = 2, since we want all the terms to be positive
- n = 10 = number of terms to sum up
So,
Sn = a*(1 - r^n)/(1 - r)
S10 = 4*(1 - 2^10)/(1 - 2)
S10 = 4*(1 - 1024)/(-1)
S10 = 4*(-1023)/(-1)
S10 = 4092
The correct answer to this question is C. equation, –3
The equation is
<span>y = 9x - 4x^2
</span>y = -4x^2 + 9x
y = -x(4x - 9)
The steepest rate of change from x = 1 to x =2
x = -1 ; y = 0
x = 1 ; y = 2
x = 2 ; y = 0
x =3 ; y = -4
So, based from the table show, the steepest rate of change is <span>C. equation, –3</span>
