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sammy [17]
3 years ago
10

Christine has always been weak in mathematics. Based on her performance prior to the final exam in Calculus, there is a 40% chan

ce that she will fail the course if she does not have a tutor. With a tutor, her probability of failing decreases to 10%. There is only a 50% chance that she will find a tutor at such short notice.
Mathematics
1 answer:
azamat3 years ago
6 0

Answer:

There are a 25% probability that Christine fails the course.

Step-by-step explanation:

We have these following probabilities:

A 50% probability that Christine finds a tutor.

With a tutor, she has a 10% probability of failling.

A 50% probability that Christine does not find a tutor.

Without a tutor, she has a 40% probability of failing.

Probability that she fails:

10% of 50%(fail with a tutor) plus 40% of 50%(fail without a tutor). So

P = 0.1*0.5 + 0.4*0.5 = 0.25

There are a 25% probability that Christine fails the course.

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V/-8 = 4v
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PLEASE HELP
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QUESTION A

The given multiplication problem is

\frac{39}{64} \times \frac{8}{13}

Factor each term to obtain;

\frac{13\times 3}{8\times8} \times \frac{8}{13}

Cancel out the common factors to obtain;

\frac{1\times 3}{8\times1} \times \frac{1}{1}

Simplify to get;

\frac{3}{8}

QUESTION B

The given multiplication problem is

\frac{2}{3}\times \frac{1}{5}\times \frac{4}{7}

This the same as

\frac{2\times 1\times 4}{3\times 5\times 7}

This simplifies to;

\frac{8}{105}

QUESTION C

The given problem is

\frac{3}{5}\times \frac{10}{12} \times \frac{1}{2}

This is the same as

\frac{3}{5}\times \frac{5}{6} \times \frac{1}{2}

=\frac{1}{1}\times \frac{1}{2} \times \frac{1}{2}

This simplifies to

=\frac{1}{4}

QUESTION D.

The given expression is

\frac{4}{9}\times 54

Factor the 54 to obtain;

\frac{4}{9}\times 9\times 6

Cancel the common factors to get;

\frac{4}{1}\times 1\times 6

This simplifies to;

=24

QUESTION E

The given problem is

20\times 3\frac{1}{5}

Convert the mixed numbers to improper fraction to obtain;

=20\times \frac{16}{5}

=4\times5 \times \frac{16}{5}

Cancel the common factors to get;

=4\times1 \times \frac{16}{1}

=64

QUESTION F

The multiplication problem is

11 \times 2 \frac{7}{11}

Convert the mixed numbers to improper fractions to obtain;

11 \times \frac{29}{11}

Cancel out the common factors to get;

=1 \times \frac{29}{1}

Simplify;

=29

QUESTION G

The given problem is

5\frac{1}{3}\times 5\frac{1}{8}

Convert to improper fractions;

=\frac{16}{3}\times \frac{41}{8}

Cancel out the common factors to get;

=\frac{2}{3}\times \frac{41}{1}

=\frac{82}{3}

Convert back to mixed numbers

=27\frac{1}{3}

QUESTION H

The given expression is

10\frac{2}{3} \times 1\frac{3}{8}

Convert to improper fraction to get;

\frac{32}{3} \times \frac{11}{8}

Cancel common factors to get;

=\frac{4}{3} \times \frac{11}{1}

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Convert back to mixed numbers;

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Ratio = 63/105

Reduce to the least fraction

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H/144 = 3/5

H = (144 x3)/5

H = 86.4

Therefore the lamppost is approximately 86 inches, that is 7 feet and 2 inches tall.

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