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Aneli [31]
2 years ago
10

Sandy can fold 6 towels in 3 minutes. If she continues at this rate, how many minutes will it take her to fold 36 towels?

Mathematics
1 answer:
AveGali [126]2 years ago
8 0

Answer:

18 minutes

Step-by-step explanation:

6 towels in 3 minutes

36 towels = ?

36/6 x 3

= 18

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MVUT =175, mVUJ=17x-3, and mJUT=17x+8. Find x
kotykmax [81]
The diagram of the three angles is shown below with point U as the point where all three lines meet.

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5 0
3 years ago
Researchers studying starfish collected two independent random samples of 40 starfish. One sample came from an ocean area in the
krek1111 [17]

Answer:

The test statistic for the appropriate test is \frac{0.15-0.275}{\sqrt{0.2125(1-0.2125)[\frac{1}{40}+\frac{1}{40}]}}.

Step-by-step explanation:

The experiment conducted here is to determine whether there is a difference in proportion of starfish over 8 inches in length in the two ocean areas, i.e. north and south.

The hypothesis to test this can be defined as follows:

<em>H₀</em>: There is no difference in proportion of starfish over 8 inches in length in the two ocean areas, i.e. <em>p</em>₁ = <em>p</em>₂.

<em>Hₐ</em>: There is a difference in proportion of starfish over 8 inches in length in the two ocean areas, i.e. <em>p</em>₁ ≠ <em>p</em>₂.

The two-proportion <em>z</em>-test would be used to perform the test.

A sample of <em>n</em> = 40 starfishes are selected from both the ocean areas.

It provided that of the 40 starfish from the north, 6 were found to be over 8 inches in length and of  the 40 starfish from the south, 11 were found to be over 8 inches in length.

Compute the sample proportion of starfish from north that were over 8 inches in length as follows:

\hat p_{n}=\frac{6}{40}=0.15

Compute the sample proportion of starfish from south that were over 8 inches in length as follows:

\hat p_{s}=\frac{11}{40}=0.275

The test statistic is:

z=\frac{\hat p_{n}-\hat p_{s}}{\sqrt{P(1-P)[\frac{1}{n_{n}}+\frac{1}{n_{s}}]}}

Compute the combined proportion <em>P</em> as follows:

P=\frac{X_{n}+X_{s}}{n_{n}+n_{s}}=\frac{6+11}{40+40}=0.2125

Compute the test statistic value as follows:

z=\frac{\hat p_{n}-\hat p_{s}}{\sqrt{P(1-P)[\frac{1}{n_{n}}+\frac{1}{n_{s}}]}}

  =\frac{0.15-0.275}{\sqrt{0.2125(1-0.2125)[\frac{1}{40}+\frac{1}{40}]}}

Thus, the test statistic for the appropriate test is \frac{0.15-0.275}{\sqrt{0.2125(1-0.2125)[\frac{1}{40}+\frac{1}{40}]}}.

8 0
3 years ago
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