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2 years ago

Sandy can fold 6 towels in 3 minutes. If she continues at this rate, how many minutes will it take her to fold 36 towels?

Mathematics

1 answer:

AveGali [126]2 years ago

8 0

Answer:

18 minutes

Step-by-step explanation:

6 towels in 3 minutes

36 towels = ?

36/6 x 3

= 18

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-0.9+28 ---- 6 help me solve the task im a little lazy

Anvisha [2.4K]

Answer:

around 4.52.

Fraction form: $4\frac{52}{100}$

Step-by-step explanation:

Brainliest?

7 0

2 years ago

Find the solution of the system by graphing

zvonat [6]

Answer:

x = -2

y = -1

(-2, -1)

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS
Equality Properties

Algebra I

Solving systems of equations using substitution/elimination
Solving systems of equations by graphing

Step-by-step explanation:

Step 1: Define systems

y = x + 1

3x + 3y = -9

Step 2: Solve for x

Substitution

Substitute in y: 3x + 3(x + 1) = -9
Distribute 3: 3x + 3x + 3 = -9
Combine like terms: 6x + 3 = -9
Isolate x term: 6x = -12
Isolate x: x = -2

Step 3: Solve for y

Define original equation: y = x + 1
Substitute in x: y = -2 + 1
Add: y = -1

Step 4: Graph systems

Check the solution set.

6 0

2 years ago

HELP PLEASE PEOPLE THANK UUUUU ‘

Komok [63]

<h2>The required "option B) 60°" is correct.</h2>

Step-by-step explanation:

In question figure,

∠ YUV = 40°, ∠ XUY = 105° and ∠WUX = 155°

To find, the value of ∠ VUW = ?

We know that,

The circle having 360°

∴ ∠ VUW + ∠ YUV + ∠ XUY + ∠WUX = 360°

⇒ ∠ VUW + 40° + 105°+ 155° = 360°

⇒ ∠ VUW + 300° = 360°

⇒ ∠ VUW = 360° - 300°

⇒ ∠ VUW = 60°

∴ The value of ∠ VUW = 60°

Hence, the required "option B) 60°" is correct.

3 0

2 years ago

How do I solve the problem 5×7/10

katovenus [111]

Multiply 5*7, then take that product and divide by 10.

3 0

3 years ago

Read 2 more answers

The coordinates of the image of line segment RT are R'(-2,-4) and T'(4.4). The image was produced by a dilation with a scale fac

Daniel [21]

Given the coordinates of the image of line segment RT to be R'(-2,-4) and T'(4.4), if the image produced was dilated by a scale factor of 12 centered at the origin, to get the coordinate of the end point, we will simply multiply the x and y coordinates of by the factor of 12 as shown:

For R' with coordinate R'(-2,-4), the coordinates of endpoint of the pre-image will be:

R = 12R'

R = 12(-2, -4)

R = (-24, -48)

For T' with coordinate T'(4,4), the coordinates of endpoint of the pre-imagee will be:

T = 12T'

T = 12(4, 4)

T = (48, 48)

Hence the coordinate of the endpoint of the preimage will be at R(-24, -48) and T(48, 48)

6 0

11 months ago