

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


[ log (x) + log (y) = log (xy) ]








The only possible value of x is 3, since we can't operate logarithm with a negative integer in it.

Answered by : ❝ AǫᴜᴀWɪᴢ ❞
I hope this helps you
y=x^2-81
x^2=y+81
x=square root of y+81
f^-1 (x)= square root of x+81
Solution:
<u>Convert the fractions into improper fractions and solve.</u>
- 9 1/2 ÷ 3 7/10
- => 19/2 ÷ 37/10
- => 19/2 x 10/37
- => 19 x 5/37
- => 95/37
<u>Convert the fraction into mixed fraction (Not required):</u>
- => 95/37 = 37/37 + 37/37 + 21/37
- => 1 + 1 + 21/37
- => 2 + 21/37
- => 2 21/37
The solution to the problem is 2 21/37.
Answer:
-9 degrees Celsius
Step-by-step explanation:
mark brainliest if helped :)
Answer:
English? and for that matter