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yawa3891 [41]
3 years ago
14

Find the product of 2x^4(4x^2 + 3x + 1).

Mathematics
1 answer:
lianna [129]3 years ago
5 0
We want to find the product:

                         \displaystyle{ 2x^4\cdot(4x^2 + 3x + 1).

By the \text{Distributive property}, we distribute 2x^4 over each of the three terms inside the parenthesis:

\displaystyle{ 2x^4\cdot(4x^2 + 3x + 1)=2x^4\cdot4x^2+2x^4\cdot3x+2x^4\cdot1.

Multiplying the coefficients, and adding the exponents we get:

8x^6+6x^5+2x^4.


Answer: 8x^6+6x^5+2x^4.
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Step-by-step explanation:

-t = 9(t-10)

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90 = 9t + t

90 = 10t

90 ÷ 10 = t

9 = t

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Graph the solution of y – 2 &gt; 1 on a number line.
Hunter-Best [27]
<span> y-2 > 1
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3 years ago
What is the rule for this pattern? 1st term:32, 2nd term:36, 3rd<br>term:40​
Alenkasestr [34]

Answer:

Add four to each sum

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32, 36, 40

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Hope this helped!

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4 0
3 years ago
Read 2 more answers
A given population proportion is .25. What is the probability of getting each of the following sample proportions
anyanavicka [17]

This question is incomplete, the complete question is;

A given population proportion is .25. What is the probability of getting each of the following sample proportions

a) n = 110 and = p^ ≤ 0.21, prob = ?

b) n = 33 and p^ > 0.24, prob = ?

Round all z values to 2 decimal places. Round all intermediate calculation and answers to 4 decimal places.)

Answer:

a) the probability of getting the sample proportion is 0.1660

b) the probability of getting the sample proportion is 0.5517

Step-by-step explanation:

Given the data in the questions

a)

population proportion = 0.25

q = 1 - p = 1 - 0.25 = 0.75

sample size n = 110

mean = μ = 0.25

S.D = √( p( 1 - p) / n ) = √(0.25( 1 - 0.25) / 110 ) √( 0.1875 / 110 ) = 0.0413

Now, P( p^ ≤ 0.21 )

= P[ (( p^ - μ ) /S.D) < (( 0.21 - μ ) / S.D)

= P[ Z < ( 0.21 - 0.25 ) / 0.0413)

= P[ Z < -0.04 / 0.0413]

= P[ Z < -0.97 ]

from z-score table

P( X ≤ 0.21 ) = 0.1660

Therefore, the probability of getting the sample proportion is 0.1660

b)

population proportion = 0.25

q = 1 - p = 1 - 0.25 = 0.75

sample size n = 33

mean = μ = 0.25

S.D = √( p( 1 - p) / n ) = √(0.25( 1 - 0.25) / 33 ) = √( 0.1875 / 33 ) = 0.0754

Now, P( p^ > 0.24 )  

= P[ (( p^ - μ ) /S.D) > (( 0.24 - μ ) / S.D)

= P[ Z > ( 0.24 - 0.25 ) / 0.0754 )

= P[ Z > -0.01 / 0.0754  ]

= P[ Z > -0.13 ]

= 1 - P[ Z < -0.13 ]

from z-score table

{P[ Z < -0.13 ] = 0.4483}

1 - 0.4483

P( p^ > 0.24 )  = 0.5517

Therefore, the probability of getting the sample proportion is 0.5517

6 0
2 years ago
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