9514 1404 393
Answer:
y -2 = 2(x -2)
Step-by-step explanation:
The slope of the line is given by the slope formula:
m = (y2 -y1)/(x2 -x1)
m = (4 -2)/(3 -2) = 2/1 = 2
The point-slope form of the equation for the line is ...
y -k = m(x -h) . . . . . . line with slope m through point (h, k)
For the first point and the slope we found, the equation is ...
y -2 = 2(x -2)
__
You can rearrange this to any form you may like.
y -2 = 2x -4 . . . eliminate parentheses
y = 2x -2 . . . . . slope-intercept form
2x -y = 2 . . . . . standard form
Answer:
17
Step-by-step explanation:
Since we are evaluating <em>g(x)</em> for g(4), we would substitute <em>x</em> in the equation with 4.
<em>x</em>² + 1
(4)²+ 1
16 + 1
17
I hope this helps
X=-4 that might be the correct awnser
Answer:
x = 53
y = 30
Step-by-step explanation:
Step(I):-
Given equations are
x -2y =-7 ...(I)
5x-9y =-5 ..(ii)
The matrix form AX = B
![\left[\begin{array}{ccc}1&-2\\ 5 & -9\\\end{array}\right] \left[\begin{array}{ccc}x\\y\\\end{array}\right] = \left[\begin{array}{ccc}-7\\-5\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%26-2%5C%5C%205%20%20%26%20-9%5C%5C%5Cend%7Barray%7D%5Cright%5D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Dx%5C%5Cy%5C%5C%5Cend%7Barray%7D%5Cright%5D%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-7%5C%5C-5%5C%5C%5Cend%7Barray%7D%5Cright%5D)
The determinant
By using Cramer's Rule
Δ₁ = ![\left[\begin{array}{ccc}-7&-2\\\\-5&-9\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-7%26-2%5C%5C%5C%5C-5%26-9%5Cend%7Barray%7D%5Cright%5D)
The determinant is Δ₁ = -9 X -7 - (10 ) = 53
x = Δ₁ / Δ
x = 53
The determinant
Δ₂ =
Δ₂ = -5 +35
y = Δ₂/Δ = 30
This is not picture so I don’t know what to do !
