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levacccp [35]
3 years ago
14

What fitness gram component would you do in order to increase your flexibility?

Mathematics
1 answer:
Wittaler [7]3 years ago
8 0

Answer:

Cardiovascular Endurance.

Muscular Strength.

Muscular endurance.

Flexibility.

Body Composition.

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eduard

bakers a and d


[6:4 is the same as 3:2]


(hope this helps, if so, please give brainliest x)

7 0
3 years ago
If the slope of a line is 2 and the y-intercept is 7, what would the equation be in slope intercept form?
Artist 52 [7]

Answer:

y = 2x+7

Step-by-step explanation:

y = mx + c

m = slope

c is the y intercept

so

y = 2x+ 7

6 0
2 years ago
How many tons are in 16000
Svetach [21]

Answer: 8 tons

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
What does the fundamental theorem of algebra illustrate?
UNO [17]

Answer:

The fundamental theorem of algebra guarantees that a polynomial equation has the same number of complex roots as its degree.

Step-by-step explanation:

The fundamental theorem of algebra guarantees that a polynomial equation has the same number of complex roots as its degree.

We have to find the roots of this given equation.

If a quadratic equation is of the form ax^{2}+bx +c=0

Its roots are \frac{-b+\sqrt{b^{2}-4ac } }{2a} and \frac{-b-\sqrt{b^{2}-4ac } }{2a}

Here the given equation is 2x^{2}-4x-1 = 0

a = 2

b = -4

c = -1

If the roots are x_{1} and x_{2}, then

x_{1} = \frac{-2+\sqrt{(-4)^{2}-4\times 2\times (-1)}}{2\times 2}

                       = \frac{4 +\sqrt{24}}{4}

                       = \frac{2+\sqrt{6} }{2}

x_{2} = \frac{-2-\sqrt{(-4)^{2}-4\times 2\times (-1)}}{2\times 2}

                        = \frac{4 +\sqrt{8}}{4}

                        = \frac{2-\sqrt{6} }{2}

These are the two roots of the equation.

6 0
3 years ago
6x+4y=22<br> 2x-y=1<br> solve by elimination
liq [111]
6x + 4y = 22
+
2x - y = 1
____________
8x + 3y = 23
3 0
3 years ago
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