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prohojiy [21]
3 years ago
12

Write the pseudocode for a function named timesTen that accepts an Integer argument. When the function is called, it should retu

rn the value of its argument multiplied times 10. Write a main module that asks the user to enter a number, call the timesTen function, passing in that number as and argument, receives the return value, and displays the returned value in a user-friendly message.
Computers and Technology
1 answer:
iren [92.7K]3 years ago
3 0

Answer:

function timesTen (number):

   return number * 10

n = int(input("Enter an integer: "))

print(str(n) +"x10 is equal to: " + str(timesTen(n)))

Explanation:

Pseudocode is the representation of an algorithm. It shows the steps of the algorithm combination of the English and programming language.

In the pseudocode, we said we will be defining a function called timesTen that takes one parameter and returns the value of its parameter multiplied times 10.

In the main, we asked the user to enter a number. Then, we called the function with that number, and print the result.

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The ratio of boys and girls is 4:5 calculate the number of boys if the are 1080 learners in schools​
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Explanation:

The ratio of Boys =  4x

The ratio of  Girls =  5x

The Number of Boys in the School = 4x + 5x = 1080

                                                          =         9x = 1080

                                                          =           x  = 1080/9

<em>                                                          </em> =           x  = 120

The ratio of Boys = 4x  = 4 x 120 = <em>480</em>

The ratio of  Girls =  5x = 5 x 120 = 600

<u></u>

Answer :-   <u><em>The ratio of Boys =480</em></u>

                 

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Answer:

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A security administrator is reviewing the following information from a file that was found on a compromised host: Which of the f
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Answer:

C. Trojan

Explanation:

In Cybersecurity, vulnerability can be defined as any weakness, flaw or defect found in a software application or network and are exploitable by an attacker or hacker to gain an unauthorized access or privileges to sensitive data in a computer system.

This ultimately implies that, vulnerability in a network avail attackers or any threat agent the opportunity to leverage on the flaws, errors, weaknesses or defects found in order to compromise the security of the network.

In this scenario, a security administrator is reviewing the following information from a file that was found on a compromised host: "cat suspiciousfile.txt."

Some of the ways to prevent vulnerability in a network are;

1. Ensure you use a very strong password with complexity through the use of alphanumerics.

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8 0
3 years ago
2. Consider a 2 GHz processor where two important programs, A and B, take one second each to execute. Each program has a CPI of
allsm [11]

Answer:

program A runs in 1 sec in the original processor and 0.88 sec in the new processor.

So, the new processor out-perform the original processor on program A.

Program B runs in 1 sec in the original processor and 1.12 sec in the new processor.

So, the original processor is better then the new processor for program B.

Explanation:

Finding number of instructions in A and B using time taken by the original processor :

The clock speed of the original processor is 2 GHz.

which means each clock takes, 1/clockspeed

= 1 / 2GH = 0.5ns

Now, the CPI for this processor is 1.5 for both programs A and B. therefore each instruction takes 1.5 clock cycles.

Let's say there are n instructions in each program.

therefore time taken to execute n instructions

= n * CPI * cycletime = n * 1.5 * 0.5ns

from the question, each program takes 1 sec to execute in the original processor.

therefore

n * 1.5 * 0.5ns = 1sec

n = 1.3333 * 10^9

So, number of instructions in each program is 1.3333 * 10^9

the new processor :

The cycle time for the new processor is 0.6 ns.

Time taken by program A = time taken to execute n instructions

=  n * CPI * cycletime

= 1.3333 * 10^9 * 1.1 * 0.6ns

= 0.88 sec

Time taken by program B = time taken to execute n instructions

= n * CPI * cycletime

= 1.3333 * 10^9 * 1.4 * 0.6

= 1.12 sec

Now, program A runs in 1 sec in the original processor and 0.88 sec in the new processor.

So, the new processor out-perform the original processor on program A.

Program B runs in 1 sec in the original processor and 1.12 sec in the new processor.

So, the original processor is better then the new processor for program B.

5 0
3 years ago
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