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Dima020 [189]
3 years ago
14

In the web form you are creating, you want a multiple-option select list to appear with five options. which line of html code wi

ll help accomplish this
Computers and Technology
1 answer:
suter [353]3 years ago
5 0
You will use a <select> for this. For example:

<select name="choice">
  <option>First</option>
  <option>Second</option>
  <option>Third</option>
  <option>Fourth</option>
  <option>Fifth</option>
</select>
You might be interested in
Write a program to calculate the great circle distance between two points on the surface of a sphere. If p1(x1, y1) and p2(x2,y2
Tamiku [17]

Answer:

import java.lang.*;

public class distance { public static double distance(double latitude1,

                                     double latitude2, double longitude1,

                                     double longitude2)

       {

      // Convert Latitude and Longitude to Radians

           longitude1 = Math.toRadians(longitude1);

           longitude2 = Math.toRadians(longitude2);

           latitude1 = Math.toRadians(latitude1);

           latitude2 = Math.toRadians(latitude2);

           

           double d_longitude = longitude2 - longitude1;

           double d_latitude = latitude2 - latitude1;

           double a = Math.pow(Math.sin(d_latitude / 2), 2)

                   + Math.cos(latitude1) * Math.cos(latitude2)

                   * Math.pow(Math.sin(d_longitude / 2),2);

           double val = 2 * Math.asin(Math.sqrt(a));

           // Radius of earth in kilometers is 6371

           double earth_radius = 6371;

           // Calculate and return the distance

           return(val * earth_radius);

       }

       // Main Method

       public static void main(String[] args)

       {

           double latitude1 = 67.32055555555556;

           double latitude2 = 83.31861111111111;

           double longitude1 = -1.7217899;

           double longitude2 = -1.6567799;

           System.out.println(distance(latitude1, latitude2,

                   longitude1, longitude2) + " K.M");

       }

   }

Explanation:

This program is implemented in Java programming language

The formula for the shortest distance between two points on the earth is:

Distance = 3963.0 * arccos[(sin(lat1) * sin(lat2)) + cos(lat1) * cos(lat2) * cos(long2 – long1)]

The latitude and longitude of the two points must be known

The latitude and longitude are converted into radians using built in methods in java.

Take value for the radius of the earth in Kilometers  6371;

Note that a seperate method has been created to calculate the distance

In the driver method (main), values for latitude and logitudes for both places have been hard-corded, then the method distance is called and passed those values

Note also that the distance has been calculated in Kilometers

8 0
3 years ago
An index purports to speed data retrieval. you, therefore, index every attribute in each table. select the likely consequence.
stira [4]

Answer:

b. data entry slows as every INSERT , UPDATE, or DELETE statement must also update every index.

Explanation:

This process help to improve the speed of get data , it takes each element in the indexed column and save the location to get faster the data. But if you index every attribute in a table it going to take a lot of time locating each column in the respective index in each query(update, delete and insert). For that reason is necesary be carefull with this process and only put index in the relevant columns

4 0
3 years ago
Write a script that calculates the common factors between 8 and 24. To find a common factor, you can use the modulo operator (%)
AnnyKZ [126]

Answer:

  1. common = []
  2. num1 = 8
  3. num2 = 24
  4. for i in range(1, num1 + 1):
  5.    if(num1 % i == 0 and num2 % i == 0):
  6.        common.append(i)
  7. print(common)

Explanation:

The solution is written in Python 3.

Firstly create a common list to hold a list of the common factor between 8 and 24 (Line 1).

Create two variables num1, and num2 and set 8 and 24 as their values, respectively (Line 3 - 4).

Create a for loop to traverse through the number from 1 to 8 and use modulus operator to check if num1 and num2 are divisible by current i value. If so the remainder of both num1%i and num2%i  will be zero and the if block will run to append the current i value to common list (Line 6-8).

After the loop, print the common list and we shall get [1, 2, 4, 8]

8 0
3 years ago
How is kerning used in Word?
kirill115 [55]

Answer: To adjust the spacing between characters that make up a word

Explanation: Kerning refers to the way spacing between two specific characters is adjusted. The idea is to give a better looking result by reducing the spacing between characters that fit together nicely (such as "A" and "V") and increasing the spacing between characters that don't. Select the text that you want to change.

4 0
2 years ago
A testing lab wishes to test two experimental brans of outdoor pain long each wiil last befor fading . The testing lab makes six
Simora [160]

Answer:

The answer is "\bold{Brand \ A \ (35, 350, 18.7) \ \ Brand \ B \ (35, 50, 7.07)}"

Explanation:

Calculating the mean for brand A:

\to \bar{X_{A}}=\frac{10+60+50+30+40+20}{6}  =\frac{210}{6}=35

Calculating the Variance for brand A:

\sigma_{A}^{2}=\frac{\left ( 10-35 \right )^{2}+\left ( 60-35 \right )^{2}+\left ( 50-35 \right )^{2}+\left ( 30-35 \right )^{2}+\left ( 40-35 \right )^{2}+\left ( 20-35 \right )^{2}}{5} \\\\

     =\frac{\left ( -25 \right )^{2}+\left ( 25  \right )^{2}+\left ( 15\right )^{2}+\left ( -5 \right )^{2}+\left ( 5 \right )^{2}+\left ( 15 \right )^{2}}{5} \\\\ =\frac{625+ 625+225+25+25+225}{5} \\\\ =\frac{1750}{50}\\\\=350

Calculating the Standard deviation:

\sigma _{A}=\sqrt{\sigma _{A}^{2}}=18.7

Calculating the Mean for brand B:

\bar{X_{B}}=\frac{35+45+30+35+40+25}{6}=\frac{210}{6}=35

Calculating the Variance for brand B:

\sigma_{B} ^{2}=\frac{\left ( 35-35 \right )^{2}+\left ( 45-35 \right )^{2}+\left ( 30-35 \right )^{2}+\left ( 35-35 \right )^{2}+\left ( 40-35 \right )^{2}+\left ( 25-35 \right )^{2}}{5}

    =\frac{\left ( 0 \right )^{2}+\left ( 10 \right )^{2}+\left ( -5 \right )^{2}+\left (0 \right )^{2}+\left ( 5 \right )^{2}+\left ( -10 \right )^{2}}{5}\\\\=\frac{0+100+25+0+25+100}{5}\\\\=\frac{100+25+25+100}{5}\\\\=\frac{250}{5}\\\\=50

 Calculating the Standard deviation:  

\sigma _{B}=\sqrt{\sigma _{B}^{2}}=7.07

4 0
3 years ago
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