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Ilya [14]
3 years ago
10

What diagonals does a kite intersect at?

Mathematics
1 answer:
Romashka [77]3 years ago
3 0
The diagonals of a kite meet at a right angle.
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Write the quadratic function 5x2 - 40x + 60 in its vertex form by completing the square. Then
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There’s no turning point bc the multiplicity is one

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3 years ago
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find an equation of the tangent line to the curve at the given point. y=sqrt(x) (1,1) Ive never been good with these equations a
Nady [450]
Equation of a tangent line of a curve is:
y- y0 = f´ (x0) (x - x0 ).   In this case: x0=1, y0=1
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f´(x0)=\frac{1}{2}
y - 1 = 1/2 ( x - 1 )
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4 0
3 years ago
There was no more rainfall for the rest of the day.
Aleonysh [2.5K]
There’s no exact value listed on this graph, but it would be where the line ends completely on the far right. The rain was fluctuating throughout the day when the graph was going up and down. when the graph completely stops, the rain did too.
5 0
3 years ago
How many 1/3 cubes does it take to fill a box with a width of 2 2/3 inches length 3 1/3 inches and height 2 1/3
Paladinen [302]

Answer:

560

Step-by-step explanation:

I assume 1/3 is the side length of the cubes.

There's two ways to solve this:

1. Find the volume of the box, then divide by the volume of the cubes.

Or 2. Find the number of cubes per each side length, the find the volume in terms of cubes.

Either way, we need to convert the mixed fractions to improper fractions.

W = 2⅔ = (2×3+2)/3 = 8/3 inches

L = 3⅓ = (3×3+1)/3 = 10/3 inches

H = 2⅓ = (2×3+1)/3 = 7/3 inches

Using the first method, the volume of the box is:

V = (8/3 in) (10/3 in) (7/3 in) = 560/27 in³

The volume of a cube is:

V = (1/3 in)³ = 1/27 in³

So the number of cubes in the box is:

(560/27 in³) / (1/27 in³) = 560

Using the second method, the cubes per each side of the box is:

W = (8/3 in) / (1/3 in) = 8

L = (10/3 in) / (1/3 in) = 10

H = (7/3 in) / (1/3 in) = 7

So the number of cubes is:

8 × 10 × 7 = 560

7 0
3 years ago
Look at the drawing of a triangle within a rectangle. The triangle and the rectangle have the same base, b, and height, h.
lara [203]

the total area of sections 1 and 2 is 48  square units !

<u>Step-by-step explanation:</u>

Here we have ,  The triangle and the rectangle have the same base, b, and height, h.  If the area of the triangle is 48 square units,We need to find what is the total area of sections 1 and 2 . Let's find out:

According to question , we have a triangle with same base and height as of rectangle inside a rectangle ! Following are the parameters of rectangle:

Length= b\\width= h\\

but , Area of rectangle = length(width) . Also , Area of triangle :

⇒ \frac{1}{2} (b)(h) = 48

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So , Area of rectangle =  (b)(h) = 96 . Total area of section 1 & 2 is given by :

⇒ 96=48+Area

⇒ Area=48

Therefore , the total area of sections 1 and 2 is 48 square units !

7 0
3 years ago
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